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ra1l [238]
3 years ago
8

Is this right pls...

Mathematics
2 answers:
hoa [83]3 years ago
7 0

Answer:

yes

Step-by-step explanation:

Dmitry [639]3 years ago
6 0
Yuppp, it is correct!
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Rick bought 3 shirts for $18 each, 2 pair of socks for $3.99 a pair, and a pair of slacks, for $45.00. The sales tax is 8.5%. Ho
ivolga24 [154]
Price of 3 shirts=$18*3=$54
Price of 2 pair of socks=2*$3.99=$7.98
Price of a pair of slack=$45
Total amount- $54+$7.98+ $45-$106.98
Sales tax rate = 8.5%
8.5% of total amount-8.5% of $106.98=
(8.5/100)*106.98-9.0933
Total amount Rick paid=$106.98+9.0933=$116.0733
Regards
6 0
3 years ago
Sooo..... can anybody help.....
Margaret [11]
V= wlh so the answer is 56.25 or 56 1/4
4 0
3 years ago
Read 2 more answers
0.6x = 31.2 ( it's multiplication)​
Rasek [7]
X = 52 would be the answer you get.

Explanation you would divide both sides by 0.6 which leaves the x and by dividing 31.2 divided by 0.6 it gives you 52
8 0
3 years ago
Let v = (v1, v2) be a vector in R2. Show that (v2, −v1) is orthogonal to v, and use this fact to find two unit vectors orthogona
andrey2020 [161]

Answer:

a. v.v' = v₁v₂ -  v₁v₂ = 0 b.  (20, -21)/29 and  (-20,21)/29

Step-by-step explanation:

a. For two vectors a, b to be orthogonal, their dot product is zero. That is a.b = 0.

Given v = (v₁, v₂) = v₁i + v₂j and v' =  (v₂, -v₁) = v₂i - v₁j, we need to show that v.v' = 0

So, v.v' = (v₁i + v₂j).(v₂i - v₁j)

= v₁i.v₂i + v₁i.(- v₁j) + v₂j.v₂i + v₂j.(- v₁j)

= v₁v₂i.i - v₁v₁i.j + v₂v₂j.i - v₂v₁j.j

i.i = 1, i.j = 0, j.i = 0 and j.j = 1

So, v.v' = v₁v₂i.i - v₁v₁i.j + v₂v₂j.i - v₂v₁j.j  

= v₁v₂ × 1 - v₁v₁ × 0 + v₂v₂ × 0 - v₂v₁ × 1

= v₁v₂ - v₂v₁

=  v₁v₂ -  v₁v₂ = 0

So, v.v' = 0

b. Now a vector orthogonal to the vector v = (21,20) is v' = (20,-21).

So the first unit vector is thus a = v'/║v'║ = (20, -21)/√[20² + (-21)²] = (20, -21)/√[400 + 441] = (20, -21)/√841 = (20, -21)/29.

A unit vector perpendicular to a and parallel to v is b = (-21, -20)/29. Another unit vector perpendicular to b, parallel to a and perpendicular to v is thus a' = (-20,-(-21))/29 = (-20,21)/29

8 0
3 years ago
The radius of a nitrogen atom is 5.8*10^-11 meters, and the radius of a beryllium atom is 1.12*10^-10 meters. Which atom has a l
Burka [1]
Nitrogen Radius = 5.8 x 10⁻¹¹ m

Beryllium Radius = 1.12 x 10⁻¹⁰ m

Let's find the quotient of N/Be :

(5.8x10⁻¹¹)/(1.12x10⁻¹⁰). But 10⁻¹¹/10⁻¹⁰ = 10⁽⁻¹¹⁺¹⁰⁾ = 10⁻¹ = 1/10 = 0.1

→ (5.8/1.12).(0.1) = 0.58/1.12 = 0.518.

Conclusion: the radius of Be is almost double than the radius of N
5 0
3 years ago
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