Let
x---------> the larger number
y---------> the smaller number
we know that
x+y=148------> equation 1
x=3y-2------> equation 2
substitute 2 in 1
[3y-2]+y=148--------> 4y=150---------> y=150/4------> y=37.5
x=3y-2----> x=3*37.5-2-----> x=110.5
the answer is
the larger number is 110.5
the smaller number is 37.5
Answer:
20.04
Step-by-step explanation:
He marked it down to 67%. Not up
Answer/Step-by-step explanation:
Let's solve your equation step-by-step.
4−(2y+5)=3(1−4y)
Step 1: Simplify both sides of the equation.
4−(2y+5)=3(1−4y)
4+−1(2y+5)=3(1−4y)(Distribute the Negative Sign)
4+−1(2y)+(−1)(5)=3(1−4y)
4+−2y+−5=3(1−4y)
4+−2y+−5=(3)(1)+(3)(−4y)(Distribute)
4+−2y+−5=3+−12y
(−2y)+(4+−5)=−12y+3(Combine Like Terms)
−2y+−1=−12y+3
−2y−1=−12y+3
Step 2: Add 12y to both sides.
−2y−1+12y=−12y+3+12y
10y−1=3
Step 3: Add 1 to both sides.
10y−1+1=3+1
10y=4
Step 4: Divide both sides by 10.
10y
10
=
4
10
y=
2
5
Answer:
y=
2/5
yw
Answer:
mean and range
arrangement before: 24,25,25,26,27
arrangement after: 24,25,25,25,26,27,28
mean before: (27+25+24+26+25)/5 = 25.4
mean after: (27+25+24+26+25+25+28))/5 = 25.7
median before: 25
median after: 25
mode before: 25
mode after: 25
range before: 24 to 27
range after: 24 to 28
hence, the mean and range were affected while the median and mode remained unchanged.