How did they get that vertex

1 answer:

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Answer:A vertex (or node) of a graph is one of the objects that are connected together. The connections between the vertices are called edges or links. A graph with 10 vertices (or nodes) and 11 edges (links).

Step-by-step explanation: (The vertex formula is derived from the completing-the-square process, just as is the Quadratic Formula. In each case, memorization is probably simpler than completing the square.) For a given quadratic y = ax2 + bx + c, the vertex (h, k) is found by computing h = –b/2a, and then evaluating y at h to find k.

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PLEASE HELP ME!!!!!!!!!!!!!!!!!!

lilavasa [31]

Answer:

a) 4 - $vt - d = \frac{1}{2} at^{2}$

b) 1 - $2(vt - d) = at^{2}$

c) 6 - $\frac{2(vt - d)}{t^{2}} = a$

Step-by-step explanation:

It simply asks the steps to go from the original displacement formula to isolate a (the acceleration). It's just a matter of moving items around.

We start with:

$d = vt - \frac{1}{2} at^{2}$

We then move the vt part on the left side, then multiply each side by -1 (to get rid of the negative on the at side and to match answer choice #4):

$vt - d = \frac{1}{2} at^{2}$

Then we multiply each side by 2 to get rid of the 1/2, answer #1:

$2(vt - d) = at^{2}$

Finally, we divide each side by t^2 to isolate a (answer #6):

$\frac{2(vt - d)}{t^{2}} = a$

4 0

3 years ago

Given the polynomial 6x3 + 4x2 − 6x − 4, what is the value of the constant 'k' in the factored form? 6x3 + 4x2 − 6x − 4 = 2(x +

CaHeK987 [17]

First you graph it using a graphing calculator, you look at the table of values to find out one point in which y= 0. The first one that comes up is when x=1.
If you don't have a graphing calculator you can use trial and error by inputing some numbers into x until you get y= 0.

Once you have an x value which makes y=0, you can start factorizing it.
you divide 6x3 +4x2 -6x - 4 into (x-1) which is when y =0
to get 6x2+10x+4

This can be used to write the polynomial as (x-1)(6x2 +10x+4)
you then factorize the second bracket, 6x2 +10x+4.
you can take the 2 outside to give you 2(3x2 +5x+2)
you can factorize this to become 2(3x+2)(x+1)

Now you just substitute your factorized second bracket into your unfactorized second bracket to give you 2(3x+2)(x+1)(x-1).

From this you can deduce that k= 1

7 0

3 years ago

Read 2 more answers

Find the product. x3(x2+5x+1)

Stella [2.4K]

Answer: x^5+5x^4+x^3

Step-by-step explanation:

assuming the expression is x^3(x^2+5x+1) each term in the bracket is multiplied by x^3

x^3(x^2+5x+1)

=(x^3*x^2)+(x^3*5x)+(x^3*1)

=x5+5x^4+x^3

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