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3 years ago

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Drag the tiles to the boxes to form correct pairs. In the diagram, transversal t cuts across the parallel lines a and b. Match t

he pairs of angles with the relationship that shows they are congruent. alternate exterior angles ∠2, ∠3 and ∠5, ∠8 alternate interior angles ∠1, ∠8 and ∠2, ∠7 corresponding angles ∠3, ∠6 and ∠4, ∠5 vertical angles ∠1, ∠5 and ∠2, ∠6 arrowBoth arrowBoth arrowBoth arrowBoth

2 answers:

yarga [219]3 years ago

7 0

Where are the type of answers for this question

yuradex [85]3 years ago

6 0

Answer:

here

alternate exterior angles--∠1, ∠8 and ∠2, ∠7

alternate interior angles--∠3, ∠6 and ∠4, ∠5

corresponding angles--∠1, ∠5 and ∠2, ∠6

vertical angles--∠2, ∠3 and ∠5, ∠8

Step-by-step explanation:

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Simplify:<br> ly - 2x - 3y + 4x

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2x-2y
I couldn’t tell if the first figure was a one or a L or i so I solved it as a 1

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2 years ago

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What is 8 1/4 divided by 3 1/2?

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2 5/14

Step-by-step explanation:

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2 years ago

Suppose there are 4 defective batteries in a drawer with 10 batteries in it. A sample of 3 is taken at random without replacemen

SSSSS [86.1K]

Answer:

a.) 0.5

b.) 0.66

c.) 0.83

Step-by-step explanation:

As given,

Total Number of Batteries in the drawer = 10

Total Number of defective Batteries in the drawer = 4

⇒Total Number of non - defective Batteries in the drawer = 10 - 4 = 6

Now,

As, a sample of 3 is taken at random without replacement.

a.)

Getting exactly one defective battery means -

1 - from defective battery

2 - from non-defective battery

So,

Getting exactly 1 defective battery = ⁴C₁ × ⁶C₂ = $\frac{4!}{1! (4 - 1 )!}$ × $\frac{6!}{2! (6 - 2 )!}$

= $\frac{4!}{(3)!}$ × $\frac{6!}{2! (4)!}$

= $\frac{4.3!}{(3)!}$ × $\frac{6.5.4!}{2! (4)!}$

= $4$ × $\frac{6.5}{2.1! }$

= $4$ × $15$ = 60

Total Number of possibility = ¹⁰C₃ = $\frac{10!}{3! (10-3)!}$

= $\frac{10!}{3! (7)!}$

= $\frac{10.9.8.7!}{3! (7)!}$

= $\frac{10.9.8}{3.2.1!}$

= 120

So, probability = $\frac{60}{120} = \frac{1}{2} = 0.5$

b.)

at most one defective battery :

⇒either the defective battery is 1 or 0

If the defective battery is 1 , then 2 non defective

Possibility = ⁴C₁ × ⁶C₂ = 60

If the defective battery is 0 , then 3 non defective

Possibility = ⁴C₀ × ⁶C₃

= $\frac{4!}{0! (4 - 0)!}$ × $\frac{6!}{3! (6 - 3)!}$

= $\frac{4!}{(4)!}$ × $\frac{6!}{3! (3)!}$

= 1 × $\frac{6.5.4.3!}{3.2.1! (3)!}$

= 1× $\frac{6.5.4}{3.2.1! }$

= 1 × 20 = 20

getting at most 1 defective battery = 60 + 20 = 80

Probability = $\frac{80}{120} = \frac{8}{12} = 0.66$

c.)

at least one defective battery :

⇒either the defective battery is 1 or 2 or 3

If the defective battery is 1 , then 2 non defective

Possibility = ⁴C₁ × ⁶C₂ = 60

If the defective battery is 2 , then 1 non defective

Possibility = ⁴C₂ × ⁶C₁

= $\frac{4!}{2! (4 - 2)!}$ × $\frac{6!}{1! (6 - 1)!}$

= $\frac{4!}{2! (2)!}$ × $\frac{6!}{1! (5)!}$

= $\frac{4.3.2!}{2! (2)!}$ × $\frac{6.5!}{1! (5)!}$

= $\frac{4.3}{2.1!}$ × $\frac{6}{1}$

= 6 × 6 = 36

If the defective battery is 3 , then 0 non defective

Possibility = ⁴C₃ × ⁶C₀

= $\frac{4!}{3! (4 - 3)!}$ × $\frac{6!}{0! (6 - 0)!}$

= $\frac{4!}{3! (1)!}$ × $\frac{6!}{(6)!}$

= $\frac{4.3!}{3!}$ × 1

= 4×1 = 4

getting at most 1 defective battery = 60 + 36 + 4 = 100

Probability = $\frac{100}{120} = \frac{10}{12} = 0.83$

3 0

2 years ago

Jared drove a distance of 165 miles to billings last weekend, which used 11 gallons of gas. How many gallons of gas will he need

blondinia [14]

Answer:

8550

Step-by-step explanation:

1. you need to figure out how many time 11 goes into 165 which is 15 then you need to get the 15 and multiply it by 570.

3 0

3 years ago

Write the augmented matrix for each system of equations.

Fudgin [204]

<u>We are given the equations: </u>

10x = 10

-5x - 8y = 9

Since we don't have a coefficient of y in the first equation, we will rewrite the first equation as:

10x + 0y = 10

<u>Writing an Augmented matrix for the 2 equations:</u>

10x + 0y = 10

-5x - 8y = 9

$\left[\begin{array}{ccc}10&0|&10\\-5&-8|&9\end{array}\right]$

5 0

3 years ago