C. x³-4x²-16x+24.
In order to solve this problem we have to use the product of the polynomials where each monomial of the first polynomial is multiplied by all the monomials that form the second polynomial. Afterwards, the similar monomials are added or subtracted.
Multiply the polynomials (x-6)(x²+2x-4)
Multiply eac monomial of the first polynomial by all the monimials of the second polynomial:
(x)(x²)+x(2x)-(x)(4) - (6)(x²) - (6)(2x) - (6)(-4)
x³+2x²-4x -6x²-12x+24
Ordering the similar monomials:
x³+(2x²-6x²)+(-4x - 12x)+24
Getting as result:
x³-4x²-16x+24
Answer:
Step-by-step explanation:
Therefore 
Answer:
The hundredths place
Expanation
6 is in the one's place
2 is in the theth's place
1 is in the hundredth's place
3 is in the thousandth's place
The number that goes into 15 and 25 is 5. So after you factor this it would be 5(3a+5b).
<u>Answer:</u>
- The solution to the problem is -38.
<u>Step-by-step explanation:</u>
- -(6m + 8) = 4(17 - m)
- => -6m - 8 = 68 - 4m
- => -6m + 4m = 68 + 8
- => -2m = 76
- => m = 76/-2
- => m = -38
Hence, <u>the solution to the problem is -38.</u>
Hoped this helped.
