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Zielflug [23.3K]
3 years ago
12

Write an equation for the line parallel to the x-axis through the point (0,-8)

Mathematics
2 answers:
WARRIOR [948]3 years ago
5 0
The answer is
y = -8
Salsk061 [2.6K]3 years ago
3 0
Y = mx + c where m is the gradient (y/x) and c is the y intercept.
Plot those coordinates into the equation ; -8 = m x 0 + c.
C = -8. The line intercepts the graph at 0,-8 so it's a flat straight line as the gradient is 0.
Therefore, all you have to do is y = mx + c, where m = 0 and c = anything apart from -8
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The number 2 in the expression 5 + 2x is called the
steposvetlana [31]

Answer:

Step-by-step explanation:

The coefficient of x is simply a number. The x gives it it's meaning. So if the coefficient of x changed from 2 to 6 that would mean there would 6 x's being added to five, not 2.

For example if x=2.

instead of 5 + 2*2

(which equals 9)

it would be 5 + 6*2

(which equals 17).

The difference between the answers is 4x, as there are an additional 4x's.

Hope this helps :)

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3 years ago
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2 years ago
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6 0
2 years ago
What’s the answer and how do you figure these out?
Nostrana [21]

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4 0
2 years ago
Use implicit differentiation to find an equation of the tangent line to the curve at the given point.
kenny6666 [7]
Hello:
Use implicit differentiation :  <span>y sin 12x = x cos 2y
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when : x = </span>π/2  and     y =π/4<span> 

</span>y' sin12(π/2) +12(π/4)cos12(π/2) =cos2(π/4) -2(π/2) y'sin2(<span>π/4)
</span>y' sin(π/6) +(π/3)cos(π/6) =cos(π/2) -  π y'sin(π/2)


y' (1/2) +(π/3)(√3/2) = -  π 

y' (1/2) =-(π/3)(√3/2)  -  π 
y'  = -π (1+√3)/3
an equation of the tangent line is : y- π/4 = ( -π (1+√3)/3)(x-<span>π/2)</span>
5 0
3 years ago
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