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Zielflug [23.3K]
4 years ago
12

Write an equation for the line parallel to the x-axis through the point (0,-8)

Mathematics
2 answers:
WARRIOR [948]4 years ago
5 0
The answer is
y = -8
Salsk061 [2.6K]4 years ago
3 0
Y = mx + c where m is the gradient (y/x) and c is the y intercept.
Plot those coordinates into the equation ; -8 = m x 0 + c.
C = -8. The line intercepts the graph at 0,-8 so it's a flat straight line as the gradient is 0.
Therefore, all you have to do is y = mx + c, where m = 0 and c = anything apart from -8
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Read 2 more answers
Find the coordinates of the midpoint (-3,13) (10,-4)
xenn [34]

Answer:

The answer is

<h2>( \frac{7}{2}  \: , \:  \frac{9}{2} )</h2>

Step-by-step explanation:

The midpoint M of two endpoints of a line segment can be found by using the formula

<h3>M = ( \frac{x1 + x2}{2}  , \:  \frac{y1 + y2}{2} )</h3>

where

(x1 , y1) and (x2 , y2) are the points

From the question the points are

(-3,13) and (10,-4)

The midpoint M is

<h3>M  = ( \frac{ - 3 + 10}{2}  , \:  \frac{13 - 4}{2} ) \\</h3>

We have the final answer as

<h3>( \frac{7}{2}  \: , \:  \frac{9}{2} )</h3>

Hope this helps you

5 0
3 years ago
8. You throw a ball downward 40 feet per second from a building
kumpel [21]

Answer:

6.16?

Step-by-step explanation:

Not completely sure but if you divide 256 by 40 you get six remainder 16 not sure if I did it right so sorry if I am wrong

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3 years ago
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