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Zielflug [23.3K]
3 years ago
12

Write an equation for the line parallel to the x-axis through the point (0,-8)

Mathematics
2 answers:
WARRIOR [948]3 years ago
5 0
The answer is
y = -8
Salsk061 [2.6K]3 years ago
3 0
Y = mx + c where m is the gradient (y/x) and c is the y intercept.
Plot those coordinates into the equation ; -8 = m x 0 + c.
C = -8. The line intercepts the graph at 0,-8 so it's a flat straight line as the gradient is 0.
Therefore, all you have to do is y = mx + c, where m = 0 and c = anything apart from -8
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Answer:

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Read 2 more answers
35 points + brainliest!
jarptica [38.1K]

Answer:

x= -2-√11. or. x= -2 + √11

Step-by-step explanation:

solving quadratic equation by completing the square

x^2+4x-7=0

x^2+4x=7

x^2+4x + (4/2)^2=7 + (4/2)^2 ( adding (1/2 coefficient of x)^2 on both sides

x^2+4x + 4=7 + 4

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(x + 2)^2=11

√(x + 2)^2= + - √11

x + 2 = + - √11

there are two different solution .

x + 2 = -√11. or x + 2 = + √11.

x= -2-√11. or. x= -2 + √11.

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