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zepelin [54]
4 years ago
8

A person invested $880 in an account growing at a rate allowing the money to double every 6 years. How much money would be in th

e account after 13 years, to the nearest dollar?
Mathematics
1 answer:
Hatshy [7]4 years ago
6 0

Answer:

  $3,951

Step-by-step explanation:

The growth factor for t years is given as 2^(t/6). Then in 13 years, the account will be multiplied by ...

  2^(13/6) ≈ 4.489848

Its value will be ...

  $880·4.489848 ≈ $3,951

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