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3 years ago

What is the value of X?

Mathematics

1 answer:

Hunter-Best [27]3 years ago

3 0

Answer:

127 degrees

Step-by-step explanation:

Because the total sum of all the angle in a hexagon is 720 degrees so in this case, x would be:

720 - 112 - 133 - 128 - 100 - 120 = 127 degrees

x would = 127 degrees

Hope this helepd :3

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Measure height of apartment building

Gre4nikov [31]

Answer:

Building height is measured from finished grade located within 2 feet of the foundation wall to the highest point on the building or structure. ... The building height is the vertical distance between finished grade and the highest point on the building, provided that the measured elevation does not include fill or berms.

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3 years ago

What expression is equivalent to the square root of -80

Ganezh [65]

Answer:

Step-by-step explanation:

√-80

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3 years ago

Read 2 more answers

Factor x^4+2x^3−2x−1 completely

goblinko [34]

1) Factor out common terms in the first two terms, then in the last two terms
{x}^{3}(x+2)-2(x+2)

2) Factor out the common term x+2
(x+2)({x}^{3}-2)

Done!

5 0

3 years ago

Solve using Fourier series.

Olin [163]

With $2L=\pi$ , the Fourier series expansion of $f(x)$ is

$\displaystyle f(x)\sim\frac{a_0}2+\sum_{n\ge1}a_n\cos\dfrac{n\pi x}L+\sum_{n\ge1}b_n\sin\dfrac{n\pi x}L$
$\displaystyle f(x)\sim\frac{a_0}2+\sum_{n\ge1}a_n\cos2nx+\sum_{n\ge1}b_n\sin2nx$

where the coefficients are obtained by computing

$\displaystyle a_0=\frac1L\int_0^{2L}f(x)\,\mathrm dx$
$\displaystyle a_0=\frac2\pi\int_0^\pi f(x)\,\mathrm dx$

$\displaystyle a_n=\frac1L\int_0^{2L}f(x)\cos\dfrac{n\pi x}L\,\mathrm dx$
$\displaystyle a_n=\frac2\pi\int_0^\pi f(x)\cos2nx\,\mathrm dx$

$\displaystyle b_n=\frac1L\int_0^{2L}f(x)\sin\dfrac{n\pi x}L\,\mathrm dx$
$\displaystyle b_n=\frac2\pi\int_0^\pi f(x)\sin2nx\,\mathrm dx$

You should end up with

$a_0=0$
$a_n=0$
(both due to the fact that $f(x)$ is odd)
$b_n=\dfrac1{3n}\left(2-\cos\dfrac{2n\pi}3-\cos\dfrac{4n\pi}3\right)$

Now the problem is that this expansion does not match the given one. As a matter of fact, since $f(x)$ is odd, there is no cosine series. So I'm starting to think this question is missing some initial details.

One possibility is that you're actually supposed to use the even extension of $f(x)$ , which is to say we're actually considering the function

$\varphi(x)=\begin{cases}\frac\pi3&\text{for }|x|\le\frac\pi3\\0&\text{for }\frac\pi3$

and enforcing a period of $2L=2\pi$ . Now, you should find that

$\varphi(x)\sim\dfrac2{\sqrt3}\left(\cos x-\dfrac{\cos5x}5+\dfrac{\cos7x}7-\dfrac{\cos11x}{11}+\cdots\right)$

The value of the sum can then be verified by choosing $x=0$ , which gives

$\varphi(0)=\dfrac\pi3=\dfrac2{\sqrt3}\left(1-\dfrac15+\dfrac17-\dfrac1{11}+\cdots\right)$
$\implies\dfrac\pi{2\sqrt3}=1-\dfrac15+\dfrac17-\dfrac1{11}+\cdots$

as required.

5 0

3 years ago

**hint** Find the hypotenuse and then subtract that from the distance he actually traveled.

icang [17]

Answer:

10 miles

Step-by-step explanation:

5 0

3 years ago