The bisector of angle APQ passes through O and this is illustrated below.
<h3>How to illustrate the information?</h3>
From the information given, the center is O. and the circle passes through O and cuts at K.
In this case, it should be noted that the circles are equal according to the SAS test.
Here, AOB + APQ = 180° (Linear pair)
2AOB = 180
AOB = 90.
Therefore, the bisector of angle APQ passes through O.
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1. 78 = 0.15x
78 / 0.15 = x
520 = x.....so 78 is 15% of 520
2. | 3x - 2 | = 8 | x + 1 | = 1
3x - 2 = 8 -(3x - 2) = 8 x + 1 = 1 -(x + 1) = 1
3x = 8 + 2 -3x + 2 = 8 x = 1 - 1 -x - 1 = 1
3x = 10 -3x = 6 x = 0 -x = 2
x = 10/3 x = -2 x = -2
ur answer is : x = -2
3. 3y - 4x + 5 = 0
3y = 4x - 5
y = 4/3x - 5/3
slope = 4/3
Check the picture below.
notice that 146° is sitting on a flat-line, and thus it has a sibling linear angle, namely 34°.
now, recalling that a triangle has a sum of 180° for all interior angles, the missing one is 126°, and incidentally that is a corresponding angle with "c".
Answer:
x=5,y=-2
Step-by-step explanation:
In this question , we have to find, which option represents inverse functions.
Let's check out option b
Let it be y
So we have
Switching x and y and solving for y,
Performing cross multiplication
Combining like terms
Which is same as of the other function.
So correct option is b .
