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2 years ago

What is the value of X?

Mathematics

1 answer:

Hunter-Best [27]2 years ago

3 0

Answer:

127 degrees

Step-by-step explanation:

Because the total sum of all the angle in a hexagon is 720 degrees so in this case, x would be:

720 - 112 - 133 - 128 - 100 - 120 = 127 degrees

x would = 127 degrees

Hope this helepd :3

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If CP =Rs. 9,000 and SP= Rs. 8,584 then Profit / loss amount is

Gemiola [76]

Answer: Loss = Rs. 416

Step-by-step explanation:

Since CP is more than SP, it is a loss.

Loss = CP - SP

Loss = 9000 - 8584

Loss = 416

8 0

3 years ago

What is 3/6 as a decimal?

iren2701 [21]

0.5 is the answer hope I helped you

5 0

3 years ago

Helps pls help pls thank you so much

Juliette [100K]

Answer:

Increases, same, increases, decreases

Step-by-step explanation:

I mean just look at the graph

7 0

3 years ago

(Inscribed Angles)

Alik [6]

Answer:

(D) 30 degrees

Step-by-step explanation:

An inscribed angle is an angle formed by two chords in a circle which have a common endpoint.

<u>Theorem(Inscribed Angles Conjecture I): </u>In a circle, the measure of an inscribed angle is half the measure of the central angle with the same intercepted arc.

By the theorem above and from the attached diagram,

Inscribed Angle p =Half of 60 degrees

$\angle p=0.5 X 60^\circ\\p=30^\circ$

<u>The correct option is D.</u>

4 0

2 years ago

A tank has capacity 6 L and initially contains 11 mg of salt dissolved in 3 L of water. A solution containing 1 mg/L of salt ent

BlackZzzverrR [31]

Answer:

The answer is below

Step-by-step explanation:

a) The maximum capacity of he tank is 6 L and initially it contains 11 mg of salt dissolved in 3 L of water. Solution enters the tank at a rate of 3 L/hr, therefore in x hours, the amount of water that have entered the tank = 3x.

Solution also leaves the tank at a rate of 2L/hr, therefore in x hours, the amount of water that have left the tank = 2x

Hence the amount of water present in the tank at x hours is given as:

3 + 3x - 2x = 3 + x

The time taken to full the tank can be gotten from:

3 + x = 6

x = 6 - 3

x = 3 hr

$\frac{dQ}{dx}=3-\frac{2Q}{3+x}\\ \\\frac{dQ}{dx}+\frac{2Q}{3+x}=3\\\\let\ u'=\frac{2u}{3+x}\\\\\frac{u'}{u}=\frac{2Q}{3+x}\\\\ln(u)=2ln(3+x)\\\\u=(3+x)^2\\\\(3+x)^2Q]'=3(3+x)^2\\\\(3+x)^2Q=(3+x)^3+c\\\\Q(0)=11\\\\(3+0)^2(11)=(3+0)^3+c\\\\x=72\\\\Q=x+3+\frac{72}{(x+3)^2}\\ \\Q(3)=3+3+\frac{72}{(3+3)^2}=8\ mg$

8 mg/ 6 L = 4/3 mg/L

8 0

3 years ago