<h2>
Hello!</h2>
The answer is:
The approximate volume is 9.84 L.
<h2>
Why?</h2>
Since we are given the numer of moles, the temperature and the pressure of the gas, we can calculate the approximate volume using The Ideal Gas Law.
The Ideal Gas Law is based on Boyle's Law, Gay-Lussac's Law, Charles's Law, and Avogadro's Law, and it's described by the following equation:
Where,
P is the pressure of the gas.
V is the volume of the gas.
n is the number of moles of the gas.
T is the absolute temperature of the gas (Kelvin).
R is the ideal gas constant, which is equal to:
So, we are given the information:
Now, substituting the given information and isolating the Volume from The Ideal Gas Law equation, we have:
So, the approximate volume is 9.84 L.
Have a nice day!
3,91·10²⁴ = 39,1·10²³
-----------------------------
110,96g ----------- 6,02·10²³ molecules
Xg ------------------ 39,1<span>·10²³ molecules
X = (110,96</span>×39,1·10²³)/<span>6,02·10²³
<u>X = 720,687g</u>
:)</span>
Answer:
138.6 g of C₂HF₃O₂ have 38.9 g of O
Explanation:
Trifluoroacetic acid → C₂HF₃O₂
Molar mass = Mass of C . 2 + Mass of H + Mass of F . 3 + Mass of O .2
Molar mass = 12 . 2 + 1 . 1 + 19 . 3 + 16 . 2 = 114 g /mol
1 mol of C₂HF₃O₂ has:
2 moles of C
1 mol of H
3 moles of F
2 moles of O
If we state the relation in mass by g we say:
114 g of C₂HF₃O₂ have 24g of C, 1 g of H, 57 g of F and 32 g of O
Let's make a rule of three:
32 g of O are contained in 114 g of C₂HF₃O₂
38.9 g of O may be contained in (38.9 . 114) / 32 = 138.6 g
Neon has filled its outer shells, therefore it is very stable and does not need to react with other elements and doesn’t form compounds.
Answer:
C.) 76.1 grams
Explanation:
To find the mass of bromine, you need to (1) convert grams AlCl₃ to moles AlCl₃ (via molar mass), then (2) convert moles AlCl₃ to moles Br₂ (via mole-to-mole ratio from reaction coefficients), and then (3) convert moles Br₂ to grams Br₂ (via molar mass). It is important to arrange your ratios/conversions in a way that allows for the cancellation of units (the desired unit should be in the numerator).
Molar Mass (AlCl₃): 26.982 g/mol + 3(35.453 g/mol)
Molar Mass (AlCl₃): 133.332 g/mol
2 AlCl₃ + 3 Br₂ --> 2 AlBr₃ + 3 Cl₂
Molar Mass (Br₂): 2(79.904 g/mol)
Molar Mass (Br₂): 159.808 g/mol
42.3 g AlCl₃ 1 mole 3 moles Br₂ 159.808 g
------------------ x ----------------- x ---------------------- x ------------------- =
133.332 g 2 moles AlCl₃ 1 mole
= 76.0 g Br₂
*Our answers are slightly different most likely because we used slightly different molar masses*
