Step 1
Find the area of one equilateral triangle
Applying the law of sines
in this problem
a=b=7 cm
C=60 degrees
so
cm²
Step 2
To calculate the area of the hexagon multiply the area of one equilateral triangle by 
![Area Hexagon=6*[49*\frac{\sqrt{3}}{4}] \\ Area Hexagon=73.5*\sqrt{3}](https://tex.z-dn.net/?f=%20Area%20Hexagon%3D6%2A%5B49%2A%5Cfrac%7B%5Csqrt%7B3%7D%7D%7B4%7D%5D%20%20%5C%5C%20Area%20Hexagon%3D73.5%2A%5Csqrt%7B3%7D%20%20)
cm²
therefore
the answer is the option
73.5 sqrt 3cm²
I cant read this. This question is not in english.
Answer:
Step-by-step explanation:
the students that are in the survey are in it because they like the subject, rather than picking students from both types of groups, the ones that aren't doing remote learning and the ones that are doing remote learning.
Answer:
#9
I can't write out the whole proof here.
it bisects, so we know BCA is congruent to DCA
abc being congruent to adc is given
AC = AC because it is a singular side
AAS
then the lines are congruent by CPCTC
