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barxatty [35]
3 years ago
13

Write the following using algebraic notation, using the letter x for any

Mathematics
1 answer:
lbvjy [14]3 years ago
4 0

9514 1404 393

Answer:

  2(x+1)

Step-by-step explanation:

  x . . . I think of a number

  x +1 . . . add 1

  2(x +1) . . . double the result

You might be interested in
At 9 o’clock in the morning, the temperature was 29 Fahrenheit it dropped 5 Fahrenheit each hour what was the temperature at 4 o
suter [353]

Answer:

-6 degrees fahrenheit

Step-by-step explanation:

7×5=35

29-35=-6

4 0
3 years ago
Identify the percent increase or decrease for exponential growth if:<br> y = 5^x
sdas [7]

Answer: 500%

Step-by-step explanation:

It is growing because the base is greater than 1 and the exponent has a positive sign

4 0
3 years ago
The 1985 Mexico City earthquake measured a magnitude 8.0 on the Richter scale. The Richter scale uses the function M (I) = log (
Travka [436]

Answer:

The correct option is C: I = 10⁸I₀.   

Step-by-step explanation:

The function of the Richter scale is:

M_{(I)} = log(\frac{I}{I_{0}})

Since the magnitude of the earthquake is 8.0, the relation between the intensity, I, with the intensity of the threshold quake, Io, is:

8.0 = log(\frac{I}{I_{0}})

10^{8} = \frac{I}{I_{0}}

I = 10^{8}I_{0}

Therefore, the correct option is C: I = 10⁸I₀.                

I hope it helps you!                    

7 0
3 years ago
Suppose a spherical balloon grows in such a way that after t seconds, its volume is V = 4 sqrt(t) cm3. What is the volume of the
Arisa [49]
:<span>  </span><span>You need to know the derivative of the sqrt function. Remember that sqrt(x) = x^(1/2), and that (d x^a)/(dx) = a x^(a-1). So (d sqrt(x))/(dx) = (d x^(1/2))/(dx) = (1/2) x^((1/2)-1) = (1/2) x^(-1/2) = 1/(2 x^(1/2)) = 1/(2 sqrt(x)). 

There is a subtle shift in meaning in the use of t. If you say "after t seconds", t is a dimensionless quantity, such as 169. Also in the formula V = 4 sqrt(t) cm3, t is apparently dimensionless. But if you say "t = 169 seconds", t has dimension time, measured in the unit of seconds, and also expressing speed of change of V as (dV)/(dt) presupposes that t has dimension time. But you can't mix formulas in which t is dimensionless with formulas in which t is dimensioned. 

Below I treat t as being dimensionless. So where t is supposed to stand for time I write "t seconds" instead of just "t".

Then (dV)/(d(t seconds)) = (d 4 sqrt(t))/(dt) cm3/s = 4 (d sqrt(t))/(dt) cm3/s = 4 / (2 sqrt(t)) cm3/s = 2 / (sqrt(t)) cm3/s. 

Plugging in t = 169 gives 2/13 cm3/s.</span>
4 0
3 years ago
Match the scale and area of each scaled object to the area of the actual object.
Kisachek [45]

Answer:

IM SORRY  BUT WHAT KIND OF MATH IS THIS

Step-by-step explanation:

6 0
2 years ago
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