in this case we have a right angled triangle, whenever you see this triangle think of the TRIG RATIOS * sin, cos & tan* but if it was another triangle besides right angled triangle you use SINE RULE OR COSINE RULE

SOLUTION

$\tan( \beta ) = \frac{opposite}{adjecent} \\ \tan( \beta ) = \frac{6}{11} \\ \beta = tan(inverse)( \frac{6}{11} ) \\ \beta = 28.61045$

5 0

1 year ago

The probability that a student guesses the correct answer to a four-choice multiple choice question is

Lilit [14]

Since we already know that there is a 25% chance to guess the correct answer to a multiple choice question, all we have to do is multiply .25 and 68 to get the expected amount of answers a student can possibly guess. We multiply .25 since it is the decimal form of 25% and 68 is our total questions.

.25 x 68 = 17

Therefore, a student can expect to guess 17 answers correct on a test with 68 multiple choice questions.

3 0

3 years ago

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