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Vladimir [108]
2 years ago
6

Tracey ran 1.200 meters in 5 minutes. How many meters/minute did she run?​

Mathematics
1 answer:
SOVA2 [1]2 years ago
4 0

Answer:

she ran 240 in a minute

Step-by-step explanation:

you have to multiply 1200 by 5 which you get 240

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Choose all the equations for which x=3 is a solution
gregori [183]

A and D

A= 3+1=4

D=4*3=12

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3 years ago
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Multiply. {}=3\dfrac{1}{2} \times 3\dfrac12=3 2 1 ​ ×3 2 1 ​
Inessa [10]

I assume you mean the product of mixed numbers,

3 1/2 × 3 1/2

If we write this as

(3 + 1/2) × (3 + 1/2) = (3 + 1/2)²

we can use the identity

(a + b)² = a² + 2ab + b²

so that

3 1/2 × 3 1/2 = 3² + (2 × 3 × 1/2) + (1/2)²

3 1/2 × 3 1/2 = 9 + 3 + 1/4

3 1/2 × 3 1/2 = 12 1/4

Alternatively, we can first write 3 1/2 as a mixed number:

3 + 1/2 = 6/2 + 1/2 = (6 + 1)/2 = 7/2

Then

3 1/2 × 3 1/2 = 7/2 × 7/2 = (7 × 7) / (2 × 2) = 49/4

and

49/4 = (48 + 1)/4 = ((4 × 12) + 1)/4 = 12 + 1/4

4 0
2 years ago
A worm moves forward 3/8 inch every 5 minutes for 1 hour 25 minutes. How fast does the worm move in this time?
Alina [70]
Multiply <span>3/8 inch by 75 and divide by 5</span>
6 0
3 years ago
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Given vectors u = (−1, 2, 3) and v = (3, 4, 2) in R 3 , consider the linear span: Span{u, v} := {αu + βv: α, β ∈ R}. Are the vec
julia-pushkina [17]

Answer:

(2,6,6) \not \in \text{Span}(u,v)

(-9,-2,5)\in \text{Span}(u,v)

Step-by-step explanation:

Let b=(b_1,b_2,b_3) \in \mathbb{R}^3. We have that b\in \text{Span}\{u,v\} if and only if we can find scalars \alpha,\beta \in \mathbb{R} such that \alpha u + \beta v = b. This can be translated to the following equations:

1. -\alpha + 3 \beta = b_1

2.2\alpha+4 \beta = b_2

3. 3 \alpha +2 \beta = b_3

Which is a system of 3 equations a 2 variables. We can take two of this equations, find the solutions for \alpha,\beta and check if the third equationd is fulfilled.

Case (2,6,6)

Using equations 1 and 2 we get

-\alpha + 3 \beta = 2

2\alpha+4 \beta = 6

whose unique solutions are \alpha =1 = \beta, but note that for this values, the third equation doesn't hold (3+2 = 5 \neq 6). So this vector is not in the generated space of u and v.

Case (-9,-2,5)

Using equations 1 and 2 we get

-\alpha + 3 \beta = -9

2\alpha+4 \beta = -2

whose unique solutions are \alpha=3, \beta=-2. Note that in this case, the third equation holds, since 3(3)+2(-2)=5. So this vector is in the generated space of u and v.

4 0
3 years ago
3x+6=30 i need some help
goldenfox [79]

Answer:

24

Step-by-step explanation:

3x+6=30

Get the co-efficient by itself

3x +6=30

     -6.   -6

3x=24

Divide by 3 on both sides

24/3

x =8

4 0
3 years ago
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