3,141......
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Answer:
Its either answer one or two. I believe it's answer one.
There are many polynomials that fit the bill,
f(x)=a(x-r1)(x-r2)(x-r3)(x-r4) where a is any real number not equal to zero.
A simple one is when a=1.
where r1,r2,r3,r4 are the roots of the 4th degree polynomial.
Also note that for a polynomial with *real* coefficients, complex roots *always* come in conjugages, i.e. in the form a±bi [±=+/-]
So a polynomial would be:
f(x)=(x-(-4-5i))(x-(-4+5i))(x--2)(x--2)
or, simplifying
f(x)=(x+4+5i)(x+4-5i)(x+2)^2
=x^4+12x^3+77x^2+196x+164 [if you decide to expand]
Answer: Joe has 20 remaining apples
[to get your answer, subtract, 35 - 5 - 5 - 5]
Answer:
x = 6/5
Step-by-step explanation:
3x - 3/5 + 2 = 5
<u>Add 3/5 and -2 on both sides.</u>
3x = 5 + 3/5 - 2
3x = 18/5
<u>Divide 3 on both sides.</u>
x = 18/5 ÷ 3
x = 18/15
x = 6/5
