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a_sh-v [17]
4 years ago
12

Anybody know the answer?

Mathematics
1 answer:
makvit [3.9K]4 years ago
5 0

The first thing we need to do is take in all this information. We already know that the answer is between 0 and 7 because Line Segment AC is equal to 7. Second of all, it is recommended to solve this problem on paper to make it easier. You write the measurement under each individual Line Segment. Now we have to try to find a way how to subtract the Line Segments in order to get the measurement of Line Segment BC. If we were to write an equation. We would get mAB + mBC + mCD + mDE = mAE . We now try to think about the values that they give us to try to simplify it as much as possible. That's all that I can give you. I am sorry. This is a pretty tough and evil question.

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32

Step-by-step explanation:

40 / 1.25=32

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A triangle has two sides of length 1 and 8. What is the smallest possible whole-number length for the third side?
valkas [14]

Answer:

8

Step-by-step explanation:

For the smallest possible length, this has to be one of the shorter sides. Let the length of this side be x.

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7 0
2 years ago
What are the domain restrictions of the expression g2−7g+10g3−6g2+8g ? Select each correct answer.
Sauron [17]

Answer with Step-by-step explanation:

We are given that an expression

f(g)=\frac{g^2-7g+10}{g^3-6g^2+8g}

We have to find domain restriction of the given function.

f(g)=\frac{(g-5)(g-2)}{g(g-4)(g-2)}

Domain restriction means : It is that value of x when substitute in function then  function will  not defined.

It means it is that values which makes denominator zero.

From given function we can see that

When substitute g=0 then it makes denominator zero.

Hence, the function is not defined at g=0

Substitute g=4

Then, it makes denominator zero.

Hence, function is not defined  at g=4

Substitute g=2

Then,it  makes denominator zero.

Hence, function is not defined  at g=2

Therefore, the function is defined for all values of g except g=0, g=2 and g=4

5 0
3 years ago
Write an equation of the line through (-1,-5) having slope 2/3. give the answer in standard form.
jekas [21]

keeping in mind that standard form for a linear equation means

• all coefficients must be integers, no fractions

• only the constant on the right-hand-side

• all variables on the left-hand-side, sorted

• "x" must not have a negative coefficient

\bf (\stackrel{x_1}{-1}~,~\stackrel{y_1}{-5})~\hspace{10em} \stackrel{slope}{m}\implies \cfrac{2}{3} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{(-5)}=\stackrel{m}{\cfrac{2}{3}}[x-\stackrel{x_1}{(-1)}]\implies y+5=\cfrac{2}{3}(x+1)

\bf \stackrel{\textit{multiplying both sides by }\stackrel{LCD}{3}}{3(y+5)=3\left( \cfrac{2}{3}(x+1) \right)}\implies 3y+15 = 2(x+1) \implies 3y+15=2x+2 \\\\\\ 3y=2x-13\implies -2x+3y=-13\implies 2x-3y=13

7 0
3 years ago
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