Answer:
x= 6, -7
Step-by-step explanation:
Answer:
W=88
Step-by-step explanation:
4*(c-66)=c
4c-66*4=c
3c=66*4
c=22*4
c=88
w=88
<span>You are to find the maximum amount of baggage that may be loaded aboard the airplane for the cg (center of gravity) to remain within the moment envelope.
In order to solve this, there is a graph that shows the load weight and the load moment of pilot and front passenger, fuel, rear passenger and passenger including the baggage. Using the given data such as pilot and front passenger 250, the load moment is 9 lbs/in, for the rear passenger at 400lbs, the load moment is 28.5 lbs/in, the fuel at 30 gal has a load moment of 2 lbs/in and oil at 8 quarters is 15 lbs. The total weight is 1,350 + 250 + 400 + 15 is 2015 lbs.</span>
Answer:
Segment U T is congruent to segment X V
Segment S T is congruent to segment W V
Angle V is congruent to angle T
Y = 40 + 4m
m = minutes
y = total papers graded
