Answer:
I think the answer is 155 ft^2. Hope this helps.
Answer:
x=-1/2
Step-by-step explanation:

and now we check

so the answer is -1/2
So,
1. Tawni swam a 50-m Freestyle in 40.8 secs.
2. Pepita swam a 100-m Butterfly in 60.2 secs.
3. Susana swam a 200-m Medley in 112.4 secs.
Manipulate the distances so that they are the same.
Tawni would swim a 200-m in 163.2 secs.
Pepita would swim a 200-m in 120.4 secs.
Susana woulld swim a 200-m in 112.4 secs.
Susana swam the fastest.
In ΔABC, D and E are the midpoints of AB and AC respectively. We know that the ratio of areas of two similar triangles is equal to the ratio of square of their corresponding sides. Hence, the ratio of the areas ΔADE and ΔABC is ar(ΔADE) : ar(ΔABC) = 1 : 4.