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olga nikolaevna [1]
2 years ago
11

Deon has bought 18 pounds of dog food. He feeds his dog

Mathematics
1 answer:
Burka [1]2 years ago
6 0

Answer:

6 to 9 meals

Step-by-step explanation:

9 If he feeds 2 pounds per meal. 18÷2 =9

6 if he feeds 3 pounds per meal. 18÷3=6

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the length of a rectagle is 5 in longer than its width. if the perimeter of the rectangle is 56 in, find its length and width
lisabon 2012 [21]

Answer:

Step-by-step explanation:

Let the width of the rectangle = x

As length is 5 inches longer than width, we have to add 5 to width

Length = x + 5

Perimeter of ractangle = 56 in

2* (length + width) = 56

2*( x + 5 + x) = 56

2* (2x + 5)    = 56

Use distributive property: a*(b +c) =(a*b) + (a * c)

2*2x + 2*5   = 56

4x  + 10 = 56

Subtract 10 from both sides

4x = 56- 10

4x = 46

Divide both sides by 4

x = 46/4

x = 11.5

Width = 11.5 in

length = 11.5 + 5

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2 years ago
How to find variables of these #2 & #3
Lubov Fominskaja [6]
So... hmmm if you check the first picture below, for 2)

we could use the proportions of those small, medium and large similar triangles  like  \bf \cfrac{small}{large}\qquad \cfrac{x}{12}=\cfrac{6}{x}\impliedby \textit{solve for "x"}
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\cfrac{small}{large}\qquad \cfrac{z}{18}=\cfrac{6}{z}\impliedby \textit{solve for "z"}
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now.. for 3) will be the second picture below


\bf \cfrac{large}{medium}\qquad \cfrac{x+10}{2\sqrt{30}}=\cfrac{2\sqrt{30}}{10}\impliedby \textit{solve for "x"}
\\\\\\
\textit{now, because you already know what "x" is, we can use it below}
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\cfrac{large}{small}\qquad \cfrac{z}{x}=\cfrac{x+10}{z}\impliedby \textit{solve for "z"}
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\textit{and let us use "x" again below}
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\cfrac{small}{medium}\qquad \cfrac{y}{10}=\cfrac{x}{y}\impliedby \textit{solve for "y"}

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3 years ago
Please help! What’s the greatest common factor?? (#10)
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(x-1) (x + 2) • 3

factor the polynomial...

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3 0
3 years ago
The perimeter of a rectangle is 640 ft. the length is 15 ft more than the width. find the are of the rectangle.
aev [14]
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4 years ago
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Answer:

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Step-by-step explanation:

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