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amm1812
3 years ago
14

Put a meme in you answer and ill give you brainiest whats 25x1053 idvided by 6

Mathematics
1 answer:
Yanka [14]3 years ago
3 0

Answer:

25 x 1053 / 6 = 4387.5

Step-by-step explanation:

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Find the surface area and volume of a cylinder with a diameter equal
dangina [55]

Answer:

Volume = 1539.38 cm³

Surface Area = 747.7 cm²

Step-by-step explanation:

Volume = πr² h

V = π(7)²(10)

V = π(49)(10)

V = 490π

V = 1539.38 cm³

Surface Area = 2πrh + 2πr²

SA = 2π(7)(10) + 2π(7)²

SA = 2π(70) + 2π(49)

SA = 140π + 98π

SA = 238π

SA = 747.7 cm²

8 0
2 years ago
1. What are the vertices of AE'F'G' for each translation?<br> a. T.6.-7)<br> (AEFG) = AE'F'G'
Anettt [7]

Answer:

i dont get the question

Step-by-step explanation:

8 0
3 years ago
Sustituir. 20c + 15r + 75p + 50e​
AVprozaik [17]

Answer:

8c - 7r + 10p - 20e

Step-by-step explanation:

Subtract (20c + 15r + 75p + 50e) - (12c + 22r + 65p + 70e)

(20c + 15r + 75p + 50e) - (12c + 22r + 65p + 70e)

Open bracket

20c + 15r + 75p + 50e - 12c - 22r - 65p - 70e

Collect like terms

= 20c - 12c + 15r - 22r + 75p - 65p + 50e - 70e

= 8c - 7r + 10p - 20e

3 0
3 years ago
Please help
pychu [463]

Answer:

<h2>        y = x² - 1</h2>

Step-by-step explanation:

y = -1 for x = 0 {point(0, -1)} means -1 at the end of formula

If we add 1 to y-coordinate of  every given point we get the squares of x-coordinate:

(1, 0):   1² - 1 = 0

(2, 3):   2² - 1 = 4 - 1 = 3

(3, 8):   3² - 1 = 9 - 1 = 8

(4, 15):   4² - 1 = 16 - 1 = 15

So for any x:

(x, y)   y = x² - 1

6 0
3 years ago
Solve the equation.
lawyer [7]

Answer:

  • x=12
  • x=9

Step-by-step explanation:

1) Eliminate parentheses:

  0.1x +18.8 = -4 +2x

  22.8 = 1.9x . . . . . . . . . add 4 - 0.1x

  12 = x . . . . . . . . . . . . . divide by 1.9

__

2) Eliminate parentheses:

  -16 +4x = 0.8x +12.8

  3.2x = 28.8 . . . . . . . . add 16 - 0.8x

  x = 9 . . . . . . . . . . . . . .divide by 3.2

_____

<em>Comments on the solutions</em>

The expression we add in each case eliminates the constant on one side of the equation and the variable term on the other side. That leaves an equation of the form ...

  variable term = constant

We choose to eliminate the smaller variable term (the one with the coefficient farthest to the left on the number line). Then the constant we eliminate is the on on the other side of the equation. This choice ensures that the remaining variable term has a positive coefficient, tending to reduce errors.

__

You can work these problems by methods that eliminate fractions. Here, the fractions are decimal values, so are not that difficult to deal with. In any event, it is good to be able to work with numbers in any form: fractions, decimals, integers. It can save some steps.

7 0
2 years ago
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