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amm1812
3 years ago
14

Put a meme in you answer and ill give you brainiest whats 25x1053 idvided by 6

Mathematics
1 answer:
Yanka [14]3 years ago
3 0

Answer:

25 x 1053 / 6 = 4387.5

Step-by-step explanation:

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Help anyone can help me do this question,I will mark brainlest. The question is find the area of the shaded region.​
Alex

Answer:

13. 10

14. 51

Step-by-step explanation:

4 0
3 years ago
What are the solution(s) for the quadratic equation?<br><br> Y=5x^2-9x+4<br><br> Show work
kakasveta [241]

Let's see

\\ \rm\rightarrowtail 5x^2-9x+4=0

\\ \rm\rightarrowtail 5x^2-5x-4x+4=0

\\ \rm\rightarrowtail 5x(x-1)-4(x-1)=0

\\ \rm\rightarrowtail (5x-4)(x-1)=0

\\ \rm\rightarrowtail x=4/5,1

8 0
2 years ago
Find the value of sec(theta°)cos(theta°) for the following values of theta. <br> b. theta = 225
Nesterboy [21]

Answer:

sec(theta°)cos(theta°) = 1  

Step-by-step explanation:

given data

(theta°) = 225

to find out

sec(theta°)cos(theta°)

solution

as we know that given equation

(theta°) = 225

cos(theta°) will be

cos(225°) = -0.7071      .................................1

so we know

sec(theta°) = \frac{1}{cos(theta)}      ..............2

so put here value of cos(theta°)

sec(theta°) = \frac{1}{-0.7071}

sec(theta°) = - 1.4142

so

sec(theta°)cos(theta°) = -0.7071  × ( - 1.4142 )

sec(theta°)cos(theta°) = 1

so answer is sec(theta°)cos(theta°) = 1  

8 0
3 years ago
Students receive 25% off the regular ticket prices at schitterbahn. if the discounted ticket is $44.25, write an equation that c
Natasha2012 [34]

Answer:

(44.25/75)*100 or (44.25/3)*4

Step-by-step explanation:

Divide by the price of $44.25 by 75 (100% - 25%) and mulitily by 100

or $44.25 by 3 and multyply by 4. (25% is a quarter 1/4, so you need 4/4)

4 0
3 years ago
How to find the radius of square that tells you length, width, and height.
Anna [14]
Well diameter will be the diagnol of that square..

let side of square be x, then diagonal will be root2 * x  = diameter

so, raidus will be = dia/ 2
 = (root2 * x ) /2

5 0
3 years ago
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