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SSSSS [86.1K]
3 years ago
11

Ilana needs d more dollars to buy a new scrapbook that costs $8.35. She has $4.88. Solve the equation $4.88+d=$8.35 to find how

much more money Ilana needs.​
Mathematics
1 answer:
omeli [17]3 years ago
6 0

Answer:

$3.47

Step-by-step explanation:

$4.88 + d = $8.35

-4.88. -4.88

d = $3.47

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Please Help!!!
Sladkaya [172]

Answer:

Step-by-step explanation:

9.05737

3 0
2 years ago
247: 10^2 and 247*10^2 what is the different about the two answers
CaHeK987 [17]
Um the 2nd one has a star
5 0
3 years ago
Evaluate the function at the given numbers( correct to six decimal places). Use the results to guess the value of the limit or e
netineya [11]

Answer:

Value of the limit is 0.5.

Step-by-step explanation:

Given,

F(x)=\frac{e^x-1-x}{x^2}

When,

x=1,F(1)=frac{e^1-1-1}{1}=e-2=0.718281

x=0.5, F(0.5)=\frac{e^0.5-1-0.5}{(0.5)^2}=0.594885

x=0.1, F(0.1)=\frac{e^0.1-1-0.1}{(0.1)^2}=0.517091

x=0.05, F(0.05)=\frac{e^0.05-1-0.05}{(0.05)^2}=0.508438

x=0.01, F(0.01)=\frac{e^0.01-1-0.01}{(0.01)^2}=0.501670 \hfill (1)

Correct upto six decimal places.

Now,

\lim_{x\to 0}F(x)=\lim_{x\to 0}\frac{e^x-1-x}{x^2}   (\frac{0}{0}) form, applying L-Hospital rule that is differentiating numerator and denominator we get,

\lim_{x\to 0}F(x)

=\lim_{x\to 0}\frac{e^x-1}{2x}    (\frac{0}{0}) form.

=\lim_{x\to 0}\frac{e^x}{2}=\frac{1}{2}=0.5\hfill (2)

Limit exist and is 0.5. That is according to (1) we can see as the value of x lesser than 1 and tending to near 0, value of the function decreases respectively. And from (2) it shows ultimately it decreases and reach at 0.5, consider as limit point of F(x).  

8 0
3 years ago
What is the radius of a circle with the equation x2 + y2 – 14x + 10y = 250?
ololo11 [35]
X2 + y2 - 14x + 10y = 250
x2 -14x + 49 - 49 + y2 + 10x + 25 - 25 = 250
(x - 7)^2 - 49 + (y+5)^2 - 25 = 250
(x-7)^2 + (y+5)^2 = 250 + 49 + 25
(x-7)^2 + (y+5)^2 = 324

Therefore the radius, r
r = 324^0.5
r = 18
4 0
3 years ago
What is the complex conjugate of -3+5i
andrew-mc [135]

Answer:

-5-2i

hope this helps :)


4 0
3 years ago
Read 2 more answers
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