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3 years ago

What is the probability that a randomly selected day of the year happens to be in December or January?

Mathematics

1 answer:

Paul [167]3 years ago

3 0

Answer:

62/365 or 62/366 depending on whether its a leap year or not

Step-by-step explanation:

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JOSIE HAS 43 ANIMAL BOOKS AND 29 ART BOOKS . SHE PUTS ALL THE BOOKS ON 8 SHELVES . SHE PUTS THE SAME NUMBER OF BOOKS ON EACH SHE

zepelin [54]

Answer:

9 books on each shelf

Step-by-step explanation:

43 + 29 = 72 books total

72/8 = 9 books per shelf

7 0

3 years ago

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PLZ HELP 13 POINTS!!!!!!!!!!

pogonyaev

Input values must have exactly one output value in order for the function to remain a function.
d. 2
f. 8
g. 15

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3 years ago

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The perimeter of a quadrilateral (four-sides polygon) is 50 inches. The longest side is three times as long as the shortest side

kkurt [141]

The side lengths of quadrilateral are 21 inches; 11 inches; 11 inches; 7 inches.

<u>SOLUTION:</u>

Given, the perimeter of a quadrilateral (four-side polygon) is 50 inches.

Let the length of shortest side be n inches. The longest side is three times as long as the shortest side.

That is, length of largest side = 3n inches

The other two sides are equally long and are 4 inches longer than the shortest side.

Then, length of remaining two sides = 4 + n inches

We have to find the length of all four sides.

Now, we know that, perimeter = 50 inches

$\begin{array}{l}{\rightarrow \text { Sum of all sides }=50} \\\\ {\rightarrow n+3 n+n+4+n+4=50} \\\\ {\rightarrow n+3 n+n+n=50-4-4} \\\\ {\rightarrow 6 n=42} \\\\ {\rightarrow n=7}\end{array}$

So, length of sides will be,

$7 \text { inches; } 3\times7=21 \text { inches; } 7+4=11 \text { inches; } 7+4=11 \text { inches. }$

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4 years ago

Choose the function whose graph is given by:

denpristay [2]

Answer:

Step-by-step explanation:

I put the equation into a GeoGebra graphing calculator, and y=sin(x-2) matches the graph.

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3 years ago

If Sn=n^2+3 then t10=?

krek1111 [17]

Answer:

T10= -21

Step-by-step explanation:

If Sn=n^2+3 then t10=?

Sn= n²+5

put n=1, 2

S1= T1 = (1)²+5

=1+5 =6

S2= n²+5

S2=(2)²+5

S2=4+5

S2=9

T2 = S2 - S1

T2 = 9-6

T2=3

T10 = a+(n-1)d

where a = 6, d = -3, n=10

T10= 6+(10-1)*-3

T10=6+(9)*-3

T10=6+(-27)

T10=6-27

T10= -21

Therefore T10= -21 ....

7 0

3 years ago