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n200080 [17]
3 years ago
6

Make x the subject a=7x/k-r

Mathematics
1 answer:
stiks02 [169]3 years ago
3 0

Answer:

x = \frac{a(k-r)}{7}

Step-by-step explanation:

Given

a = \frac{7x}{k-r} ( multiply both sides by (k - r) )

a(k - r) = 7x ( divide both sides by 7 )

\frac{a(k-r)}{7} = x

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Find all geometric sequences such that the sum of the first two terms is 24 and the sum of the first three terms is 26.
Serga [27]

Answer:

<h3>The nth term Tn = -8(-1/4)^(n-1) or Tn = 6(1/3)^(n-1) can be used to find all geometric sequences</h3>

Step-by-step explanation:

Let the first three terms be a/r, a, ar... where a is the first term and r is the common ratio of the geometric sequence.

If the sum of the first two term is 24, then a/r + a = 24...(1)

and the sum of the first three terms is 26.. then a/r+a+ar = 26...(2)

Substtituting equation 1 into 2 we have;

24+ar = 26

ar = 2

a = 2/r ...(3)

Substituting a = 2/r into equation 1 will give;

(2/r))/r+2/r = 24

2/r²+2/r = 24

(2+2r)/r² = 24

2+2r = 24r²

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4r(3r-1)+1(3r-1) = 0

(4r+1)(3r-1) = 0

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a = -8 or 6

All the geometric sequence can be found by simply knowing the formula for heir nth term. nth term of  a geometric sequence is expressed as

if r = -1/4 and a = -8

Tn = -8(-1/4)^(n-1)

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Tn = 6(1/3)^(n-1)

The nth term of the sequence above can be used to find all the geometric sequence where n is the number of terms

6 0
3 years ago
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