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ludmilkaskok [199]
3 years ago
10

Please Help!! (brainliest fr best answer)

Mathematics
1 answer:
lys-0071 [83]3 years ago
7 0

Answer:

1. E=75 degrees

Step-by-step explanation:

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\bf \begin{cases}
x=1\implies &x-1=0\\
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x=2-i\implies &x-2+i=0
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(x-1)(x-1)(2x+1)(x-2-i)(x-2+i)=\stackrel{original~polynomial}{0}
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(x^2-2x+1)(2x+1)~[(x^2-4x+4)-(-1)]
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(x^2-2x+1)(2x+1)~[(x^2-4x+4)+1]
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(x^2-2x+1)(2x+1)~[x^2-4x+5]
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of course, you can always use  (x-1)(x-1)(2x+1)(x²-4x+5)  as well.
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