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Anarel [89]
3 years ago
6

Point (-4, 3) lies in quadrant i ii iii iv user: point (6, 0) lies on the x-axis y-axis line y = x

Mathematics
2 answers:
professor190 [17]3 years ago
8 0
(-4,3) is in i
(6,0) lies on the x-axis

Studentka2010 [4]3 years ago
8 0
Point (-4,3) lies on quadrant ii
Point (6,0) lies on the x-axis
Line y=x lies on quadrant i and quadrant iii
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Can someone pls help for brainlest
gregori [183]

Diameter of the semicircle = 10 km.

Explanation:  perimeter of semicircle =   1  2

the circumference + diameter  Given: perimeter of semicircle =  25.7  k m

Circumference of circle with radius  r =  2 π r  where  2 r = diameter  ⇒ 25.7 = 22 π r + 2 r ⇒ 25.7 = π r + 2 r = r ( π + 2 )  ⇒ 25.7 = r ( 3.14 + 2 ) = r ( 5.14 )  ⇒ r = =5m ⇒d i a m e t e r = 2 r = 10 k m

5 0
3 years ago
Can someone help me please
Ksenya-84 [330]

Answer:

im not sure because im not good at these question but ill let you know when i figure it o

7 0
3 years ago
A student simplifies (6b + 4r) – (2b + r) and says that the result is 4b + 5r. Explain the error and describe the correct steps
Nezavi [6.7K]
Actually, its not 4b + 5r  its 4b +3r because look 

step 1. 6b + 4r - (2b + r)
step 2. 6b + 4r - 2b - r
step 3. (6b - 26) + (4r - r)
step 4. 4b + 3r  
So the answer is actually 4b + 3r 

hope i helped if did plz mark as <span>Brainliest</span>
7 0
3 years ago
Read 2 more answers
What is the answer to this question ?
Drupady [299]
If there is a really short way of doing this, I don't see it. The only way I know to do it is to find the third angle of both triangles. 

So for F the third angle for each of the pairs is
left side: 180 - (51 + 30) = 180 - 81 = 99
right side: 180 - (109 + 30) = 180 - 139 = 41
This is not the answer.

G
180 - (92 + 70) = 180 - 162 = 18
180 - (28 + 70) = 180 - 98 = 82
This is not the answer either.

H
180- (58 + 30) = 180 - (88) = 92
180 - (90  + 58) = 180 - 148 = 32
Not at all.

180 - (35 + 82) = 180 - 117 = 63
180 - (82 + 63) = 180 - 145 = 35
This pair has a third angle that is equal to the other triangle's pair. This is your answer.

7 0
4 years ago
If some function f has the tangent line y − 2 = 4(t − 16) at the point implied by the equation, what are f (16) and f ′(16)?
Pachacha [2.7K]

Answer:

f(16) = 2

f'(16) = 4

Step-by-step explanation:

Given:

- The function f(x) is given as:

                                   f(x) = y = 4t - 62

Find:

- what are f (16) and f ′(16)?

Solution:

- The value f(16) is given by plugging in x = 16 into the expression given as follows:

                                  f(16) = 4*16 - 62

                                  f(16) = 2

- The value of f'(16) is the gradient of the function @ x = 16.

The gradient is given by the derivative of the function:

                                  df(x) / dx = 4

Hence, f'(x) is in-dependent of the value of x and gradient is 4 for all values of x.

3 0
3 years ago
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