All categories

2 years ago

Pleaseeee help meee i dont understand

Mathematics

1 answer:

prohojiy [21]2 years ago

3 0

-(5y) - y = 18
-6y = 18
y = -3
x = 5(-3)
x = -15
(-15, -3)

5x + 4(-7x - 3) = -35
5x -28x -12 = -35
-23x = -23
x = 1
y = -7(1) - 3
y = -10
(1,-10)

You might be interested in

A squirrel ran 9 miles in 1 hour. Which expression can be used to determine its speed in miles per hour?

a_sh-v [17]

Answer:

9 mile/ 1 hour

Step-by-step explanation:

Because the squirrel ran 9 miles in 1 hour, so u have to divide 9 miles by 1 hour.

8 0

3 years ago

Read 2 more answers

What number should be added to –2 to get a sum of 2?

V125BC [204]

Answer:

Step-by-step explanation:

4 - 2 = 4 + -2 = -2 + 4

6 0

3 years ago

What is 1 + 1???????????????????????????????????????????????????

choli [55]

Answer: 2

Have a good day ¯\_(ツ)_/¯

8 0

2 years ago

Read 2 more answers

An automobile company wants to determine the average amount of time it takes a machine to assemble a car. A sample of 40 times y

aksik [14]

Answer:

A 98% confidence interval for the mean assembly time is [21.34, 26.49] .

Step-by-step explanation:

We are given that a sample of 40 times yielded an average time of 23.92 minutes, with a sample standard deviation of 6.72 minutes.

Firstly, the pivotal quantity for finding the confidence interval for the population mean is given by;

P.Q. = $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample average time = 23.92 minutes

s = sample standard deviation = 6.72 minutes

n = sample of times = 40

$\mu$ = population mean assembly time

Here for constructing a 98% confidence interval we have used a One-sample t-test statistics because we don't know about population standard deviation.

So, a 98% confidence interval for the population mean, $\mu$ is;

P(-2.426 < $t_3_9$ < 2.426) = 0.98 {As the critical value of z at 1% level

of significance are -2.426 & 2.426}

P(-2.426 < $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ < 2.426) = 0.98

P( $-2.426 \times {\frac{s}{\sqrt{n} } }$ < ${\bar X-\mu}$ < $2.426 \times {\frac{s}{\sqrt{n} } }$ ) = 0.98

P( $\bar X-2.426 \times {\frac{s}{\sqrt{n} } }$ < $\mu$ < $\bar X+2.426 \times {\frac{s}{\sqrt{n} } }$ ) = 0.98

98% confidence interval for $\mu$ = [ $\bar X-2.426 \times {\frac{s}{\sqrt{n} } }$ , $\bar X+2.426 \times {\frac{s}{\sqrt{n} } }$ ]

= [ $23.92-2.426 \times {\frac{6.72}{\sqrt{40} } }$ , $23.92+2.426 \times {\frac{6.72}{\sqrt{40} } }$ ]

= [21.34, 26.49]

Therefore, a 98% confidence interval for the mean assembly time is [21.34, 26.49] .

7 0

2 years ago

Timothy has a fenced-in garden in the shape of a rhombus. The length of the longer diagonal is 24 feet, and the length of the sh

Rzqust [24]

One property of the diagonals of a rhombus is that they are perpendicular bisectors of each other. So 4 congruent right triangles will be formed when you draw the two diagonals. Considering one right triangle, we can solve for the two sides by dividing them by 2.
24 ft/ 2 = 12 ft
18 ft/ 2 = 9 ft

Using the Pythagorean Theorem, we can now solve for the hypotenuse which is the side of the rhombus.
side = √(12²+9²) = 15 ft

The answer is B.

8 0

2 years ago

Read 2 more answers