Answer:
Q1) x = 17.3
y = 8.7
Q2) d = 19
Step-by-step explanation:
Question 1
Angle = 60°
Hypotenuse = x
Adjacent = y
Opposite = 15
<u>Step 1: Find x</u>
Sin (angle) = opposite/hypotenuse
Sin (60°) = 15/x
x = 10√3 = 17.3
<u>Step 2: Find y</u>
Tan (angle) = opposite/adjacent
Tan (60°) = 15/y
y = 5√3 = 8.7
Question 2
<u>Step 1: Find the diagonal of the base</u>
c² = a²+b²
c² = 6² + 10²
c = 2√34 = 11.7
<u>Step 2: Find diagonal d</u>
c² = a² + b²
d² = 11.7² + 15²
d = 19
!!
Answer:
c
Step-by-step explanation:
i think this is the greatest because if you solve all of the expressions you will find out that this is the greatest.
a.4×-5=-20
b.-5+4=-1
c.-4-(-5)=1
therefore 1 is the greatest so the expression c is the greatest.
I hope this helps
From the given graph, the image is a trapezoid.
Therefore,
The first option,
"t<span>
he polygon is a rectangle" is incorrect.
The second option "</span><span>Adjacent sides of the polygon are perpendicular." cannot be true as well because trapezoid has one the adjacent sides which is not perpendicular.
Third option" </span><span>Opposite sides of the polygon are parallel", this can't be true as well because only two sides are parallel.
Fourth option " </span><span>The slope of side c is 0.", this is true because line c is a horizontal line with zero rise and maximum run. Therefore,
Slope = 0 </span>÷ 9
<span> = 0
</span>
Answer:
Step-by-step explanation:
The answer is 7, Because if AC is 12 the radius would be half of that and you would get 7.
Hope I helped.
Answer:
Total number of ways will be 209
Step-by-step explanation:
There are 6 boys and 4 girls in a group and 4 children are to be selected.
We have to find the number of ways that 4 children can be selected if at least one boy must be in the group of 4.
So the groups can be arranged as
(1 Boy + 3 girls), (2 Boy + 2 girls), (3 Boys + 1 girl), (4 boys)
Now we will find the combinations in which these arrangements can be done.
1 Boy and 3 girls =
=24
2 Boy and 2 girls=![^{6}C_{2}\times^{4}C_{2}=\frac{6!}{4!\times2!}\times\frac{4!}{2!\times2!}=15\times6=90](https://tex.z-dn.net/?f=%5E%7B6%7DC_%7B2%7D%5Ctimes%5E%7B4%7DC_%7B2%7D%3D%5Cfrac%7B6%21%7D%7B4%21%5Ctimes2%21%7D%5Ctimes%5Cfrac%7B4%21%7D%7B2%21%5Ctimes2%21%7D%3D15%5Ctimes6%3D90)
3 Boys and 1 girl = ![^{6}C_{3}\times^{4}C_{1}=\frac{6!}{4!\times2!}\times\frac{4!}{3!}=\frac{6\times5\times4}{3 \times2} \times4=80](https://tex.z-dn.net/?f=%5E%7B6%7DC_%7B3%7D%5Ctimes%5E%7B4%7DC_%7B1%7D%3D%5Cfrac%7B6%21%7D%7B4%21%5Ctimes2%21%7D%5Ctimes%5Cfrac%7B4%21%7D%7B3%21%7D%3D%5Cfrac%7B6%5Ctimes5%5Ctimes4%7D%7B3%20%5Ctimes2%7D%20%5Ctimes4%3D80)
4 Boys = ![^{6}C_{4}=\frac{6!}{4!\times2!} =\frac{6\times 5}{2\times1}=15](https://tex.z-dn.net/?f=%5E%7B6%7DC_%7B4%7D%3D%5Cfrac%7B6%21%7D%7B4%21%5Ctimes2%21%7D%20%3D%5Cfrac%7B6%5Ctimes%205%7D%7B2%5Ctimes1%7D%3D15)
Now total number of ways = 24 + 90 + 80 + 15 = 209