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Tanzania [10]
3 years ago
6

kevin got 100.000+6+100+4×10+3×1 points playing the video game.Ryan got seven hundred forty thousand. sixty four pounts playing

the same game Who got the most points​
Mathematics
1 answer:
Naddika [18.5K]3 years ago
3 0

Answer:

ryan

Step-by-step explanation:

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Which statement describes a car lease?
Margaret [11]

Answer: Option C

Step-by-step explanation:

You get to use a car for a specific time period by making monthly payments

usually when you get a car lease you pick out the car and (as an example) lets say you have a 3 year lease, you will pay monthly payments for 3 years then return the car.  

6 0
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What conclusions can be drawn about finding the quotient in scientific notation? Check all that apply.
irga5000 [103]

Answer:

B.The exponent of the solution is –12, the difference of the original exponents.

C.The coefficient of the solution must be greater than or equal to one but less than 10.

D.The quotient is 3.0 ×

Step-by-step explanation:

7 0
2 years ago
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Daphne has a preloaded games card that she is using to play games at the arcade as shown in the table.
Lubov Fominskaja [6]

Answer:

she starts with $25

every three games she spends $1.50 (.50 per game)

Step-by-step explanation:

i mean i cant really explain it, its kinda self explanatory

6 0
3 years ago
Find the value of x in the triangle shown below.<br> =<br> २०<br> 14<br> 14<br> 50°<br> 18
Alexandra [31]

Answer:

x = 87

Step-by-step explanation:

37 + 56 = 93

triangles always equal to 180

180 - 93 = 87

5 0
2 years ago
If tanA=a <br>then find sin4A-2sin2A/ sin4A+2sin2A​
anygoal [31]

Answer:

The value of the given expression is

\frac{sin4A-2sin2A}{sin4A+2sin2A}=-a^2

Step by step Explanation:

Given that tanA=a

To find the value of \frac{sin4A-2sin2A}{sin4A+2sin2A}

Let us find the value of the expression :

\frac{sin4A-2sin2A}{sin4A+2sin2A}=\frac{2cos2Asin2A-2sin2A}{2cos2Asin2A+2sin2A} ( by using the formula sin2A=2cosAsinA here A=2A)  

=\frac{2sin2A(cos2A-1)}{2sin2A(cos2A+1)}

=\frac{(cos2A-1)}{(cos2A+1)}

=\frac{(-(1-cos2A))}{(1+cos2A)}(using  sin^2A+cos^2A=1  here A=2A)

=\frac{-(sin^2A+cos^2A-(cos^2A-sin^2A))}{sin^2A+cos^2A+(cos^2A-sin^2A)}(using cos2A=cos^2A-sin^2A here A=2A)

=\frac{-(sin^2A+cos^2A-cos^2A+sin^2A)}{sin^2A+cos^2A+(cos^2A-sin^2A)}

=\frac{-(sin^2A+sin^2A)}{cos^2A+cos^2A}

=\frac{-2sin^2A}{2cos^2A}

=-\frac{sin^2A}{cos^2A}

=-tan^2A  ( using tanA=\frac{sinA}{cosA} here A=2A )

 =-a^2 (since tanA=a given )

Therefore \frac{sin4A-2sin2A}{sin4A+2sin2A}=-a^2

6 0
3 years ago
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