Answer:
She can feed her rabbit for 60 days!
Step-by-step explanation:
Turn 20 into a fraction:

Make sure it has the same denominator:
<em>(Remember: what you do to one side, you must do to the other)</em>

This means that if the rabbit eats 1/3 of a pound a day, she will be able to feed her rabbit for 60 days.
When anything is bisected, the two halves are equal. This means
(-159 - 12x) = (3x + 96)
-255 = 15x . . . . . . . . . . . . . add 12x-96
-17 = x
Then either of the smaller angles is
(3(-17) + 96)° = 45°
angle ABC is twice this value, or 90°.
Answer:
Hope this helps...
Step-by-step explanation:
P stands for polynomial time. NP stands for non-deterministic polynomial time. Definitions: Polynomial time means that the complexity of the algorithm is O(n^k), where n is the size of your data (e. g. number of elements in a list to be sorted), and k is a constant.
Now, a German man named Norbert Blum has claimed to have solved the above riddle, which is properly known as the P vs NP problem.
<span>x^2+15=8x
</span><span>x^2-8x=-15
x^2 - 2 (x)(4) =-15
adding 16 on both sides
</span>x^2 - 2 (x)(4) +16=-15+16
x^2 - 2 (x)(4) + 4^2= 1
(x-4)^2=1
taking square root on bothsides x-4 = +-1
so x-4=1 or x-4=-1
x-5 or x=3
Answer:
![x= -\frac{ln [\frac{5P}{8000-P}]}{0.002}](https://tex.z-dn.net/?f=%20x%3D%20-%5Cfrac%7Bln%20%5B%5Cfrac%7B5P%7D%7B8000-P%7D%5D%7D%7B0.002%7D)
a) ![x= -\frac{ln [\frac{5*200}{8000-200}]}{0.002} =1027.062 \approx 1027](https://tex.z-dn.net/?f=%20x%3D%20-%5Cfrac%7Bln%20%5B%5Cfrac%7B5%2A200%7D%7B8000-200%7D%5D%7D%7B0.002%7D%20%3D1027.062%20%5Capprox%201027)
b) ![x= -\frac{ln [\frac{5*800}{8000-800}]}{0.002} =293.893 \approx 294](https://tex.z-dn.net/?f=%20x%3D%20-%5Cfrac%7Bln%20%5B%5Cfrac%7B5%2A800%7D%7B8000-800%7D%5D%7D%7B0.002%7D%20%3D293.893%20%5Capprox%20294)
Step-by-step explanation:
For this case we have the following function:

We can solve for x like this. First we can reorder the expression like this:



Now we can apply natura log on both sids and we got:
![ln[\frac{40000}{8000-P} -5] = ln e^{-0.002x}](https://tex.z-dn.net/?f=%20ln%5B%5Cfrac%7B40000%7D%7B8000-P%7D%20-5%5D%20%3D%20ln%20e%5E%7B-0.002x%7D)
![ln [\frac{5P}{8000-P}] = -0.002x](https://tex.z-dn.net/?f=%20ln%20%5B%5Cfrac%7B5P%7D%7B8000-P%7D%5D%20%3D%20-0.002x%20)
And if we solve for x we got:
![x= -\frac{ln [\frac{5P}{8000-P}]}{0.002}](https://tex.z-dn.net/?f=%20x%3D%20-%5Cfrac%7Bln%20%5B%5Cfrac%7B5P%7D%7B8000-P%7D%5D%7D%7B0.002%7D)
Part a
For this case we can replace P = 200 and see what we got for x like this:
![x= -\frac{ln [\frac{5*200}{8000-200}]}{0.002} =1027.062 \approx 1027](https://tex.z-dn.net/?f=%20x%3D%20-%5Cfrac%7Bln%20%5B%5Cfrac%7B5%2A200%7D%7B8000-200%7D%5D%7D%7B0.002%7D%20%3D1027.062%20%5Capprox%201027)
Part b
For this case we can replace P = 800 and see what we got for x like this:
![x= -\frac{ln [\frac{5*800}{8000-800}]}{0.002} =293.893 \approx 294](https://tex.z-dn.net/?f=%20x%3D%20-%5Cfrac%7Bln%20%5B%5Cfrac%7B5%2A800%7D%7B8000-800%7D%5D%7D%7B0.002%7D%20%3D293.893%20%5Capprox%20294)