Answer:
The estimated sum is ≈10
Step-by-step explanation:
This depends on how your professor wants you to estimate sums. Logically, though, a value of nearly 4 and a value of just over 6 add to about 10. The exact answer would be a bit over 10, at ≈10.14117
Do you mean 3/√11 ? In this case, you'll have to multiply both, numerator and denominator by the denominator ...
Answer:
Jameson will have about $267.58 less in his account than Quincy
Step-by-step explanation:
Answer:
To solve this inequality you need to get x by itself
5x<2x-3 (your first step would be to subtract 2x from each side)
3x<3 ( you then divide 3 to each side to get x by itself)
x<1
Hope this helps ;)
Step-by-step explanation:
Answer:
Second class have higher marks and greater spread.
Step-by-step explanation:
First box plot represents class first. From the first box plot, we get
Second box plot represents class second. From the second box plot, we get
First class has greater minimum value, first quartile of both classes are same, second class has greater median, first class has greater third quartile and first class has greater maximum value. It means second class have higher marks but class first have less variation.
Second class has greater range and greater inter quartile range. It means data of second class has greater spread.
Therefore, second class have higher marks and greater spread.