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PilotLPTM [1.2K]
3 years ago
14

Need help on trigonometry again​

Mathematics
1 answer:
Julli [10]3 years ago
6 0

Answer:

\fbox{3\sqrt{2}}3\sqrt2

Step-by-step explanation:

Step 1:

Let us figure out the measurements of all the angles first. We are given one angle of 45º, and another of 90º. The angles of a triangle <u>must</u> add up to 180º, hence we can use basic addition and subtraction to find the last angle.

\angle=180-90-45\\\angle=45

Great our angle is 45º! Notice something...?

Step 2:

We now have two 45º angles in our triangle. This means we have an isosceles triangle.

According to BATh (base angle theorem), <u>in an isosceles triangle, the angles opposite the congruent sides are congruent</u>. Thus, <em>y</em> is congruent to the given side of 3\sqrt2.

y=\fbox{3\sqrt{2}}3\sqrt2

<em>I hope this helps! Let me know if you have any questions :)</em>

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