Answer:
1. 15
2. 27
3. 4
4. 72
5. 2
6. 9
7. 1
Step-by-step explanation:
Answer:
6^21 = B
Step-by-step explanation:
![[6^{7} ]^{3} \\(6)^7^*^3\\6 ^{21} \\](https://tex.z-dn.net/?f=%5B6%5E%7B7%7D%20%5D%5E%7B3%7D%20%5C%5C%286%29%5E7%5E%2A%5E3%5C%5C6%20%5E%7B21%7D%20%5C%5C)
The answer is: " x < -3 " .
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Explanation:
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Given:
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" 9(2x + 1) < 9x – 18 " ;
First , factor out a "9" in the expression on the right-hand side of the inequality:
9x – 18 = 9(x – 2) ;
and rewrite the inequality:
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9(2x + 1) < 9(x – 2) ;
Now, divide EACH SIDE of the inequality by "9" ;
[9(2x + 1)] / 9 < [9(x – 2)] / 9 ;
to get:
2x + 1 < x – 2 ;
Now, subtract "x" and add "2" to each side of the inequality:
2x + 1 – x + 2 < x – 2 – x + 2 ;
to get:
x + 3 < 0 ;
Subtract "3" from EACH SIDE ;
x + 3 – 3 < 0 – 3 ;
to get:
" x < -3 " .
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Answer:
y = 5.5
Step-by-step explanation:
y = 22 * 0.5^2
=> 22* 0.25
=> 5.5
Hope this helps! :3
plz mark as brainliest!
2x2-5x-18=0
Two solutions were found :
x = -2
x = 9/2 = 4.500
Step by step solution :
Step 1 :
Equation at the end of step 1 :
(2x2 - 5x) - 18 = 0
Step 2 :
Trying to factor by splitting the middle term
2.1 Factoring 2x2-5x-18
The first term is, 2x2 its coefficient is 2 .
The middle term is, -5x its coefficient is -5 .
The last term, "the constant", is -18
Step-1 : Multiply the coefficient of the first term by the constant 2 • -18 = -36
Step-2 : Find two factors of -36 whose sum equals the coefficient of the middle term, which is -5 .
-36 + 1 = -35
-18 + 2 = -16
-12 + 3 = -9
-9 + 4 = -5 That's it
Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -9 and 4
2x2 - 9x + 4x - 18
Step-4 : Add up the first 2 terms, pulling out like factors :
x • (2x-9)
Add up the last 2 terms, pulling out common factors :
2 • (2x-9)
Step-5 : Add up the four terms of step 4 :
(x+2) • (2x-9)
Which is the desired factorization
Equation at the end of step 2 :
(2x - 9) • (x + 2) = 0
Step 3 :
Theory - Roots of a product :
3.1 A product of several terms equals zero.
When a product of two or more terms equals zero, then at least one of the terms must be zero.
We shall now solve each term = 0 separately
In other words, we are going to solve as many equations as there are terms in the product
Any solution of term = 0 solves product = 0 as well.
