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3 years ago

Find the greatest common factor of 14 and 28

Mathematics

1 answer:

Over [174]3 years ago

8 0

The greatest common factor of 14 and 28 is 14

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3 years ago

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I need help with the photo below.

PSYCHO15rus [73]

Here, 30/360 * 2πr = 10
1/12 * 2 * 3.14 * r = 10
r = 10*12 / 6.28
r = 19.11

Now, Area = 1/12 * 3.14 * (19.11)²
= 3.14/12 * 365.16
= 95.5 Ft²

In short, Your Answer would be Option C

Hope this helps!

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3 years ago

What is 190×76=? <br> Please help!

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Intravenous fluid bags are filled by an automated filling machine. Assume that the fill volumes of the bags are independent, nor

kenny6666 [7]

Answer:

a) 0.0167

b) 0

c) 5.948

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 6.16 ounces

Standard Deviation, σ = 0.08 ounces

We are given that the distribution of fill volumes of bags is a bell shaped distribution that is a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

a) Standard deviation of 23 bags

$\displaystyle\frac{S.D}{\sqrt{23}} = \frac{0.08}{\sqrt{23}} = 0.0167$

b) P( fill volume of 23 bags is below 5.95 ounces)

P(x < 5.95)

$P( x < 5.96) = P( z < \displaystyle\frac{5.95 - 6.16}{0.0167}) = P(z < -12.57)$

$= 1 - P(z < 12.57)$

Calculation the value from standard normal z table, we have,

$P(x < 5.95) = 1 - 1 = 0$

c) P( fill volume of 23 bags is below 6 ounces) = 0.001

P(x < 6) = 0.001

$P( x < 6) = P( z < \displaystyle\frac{6 - \mu}{0.0167})$

Calculation the value from standard normal z table, we have,

$P( z \leq -3.09) = 0.001$

$\displaystyle\frac{6 - \mu}{0.0167} = -3.09\\\\\mu = 6 + (0.0167\times -3.09) = 5.948$

If the mean will be 5.948 then the probability that the average of 23 bags is below 6.1 ounces is 0.001.

7 0

3 years ago

Find the greatest common factor of 14 and 28​

Find the greatest common factor of 14 and 28