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Oksi-84 [34.3K]
3 years ago
11

Which value, when placed in the box, would result in a system of equations with infinitely many solutions?

Mathematics
2 answers:
hoa [83]3 years ago
8 0

Answer:

-10

Step-by-step explanation:

ira [324]3 years ago
7 0
<span>For a system of equations to have infinitely many solutions, the equations have to be lineary dependent, (i.e. one of the equations is a multiple of the other equation). For the given equation to have infinitely many solutions, the second equation have to be a multiple of the first equation. The first equation can be rewritten as y - 2x = -5 The second equation is the first equation multiplied by 2, i.e. 2(y - 2x= -5) = 2y - 4x = -10 Therefore, the correct answer is -10 (option a).</span>
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Assume that y varies inversely
Marina86 [1]

Answer:

y = 2

Step-by-step explanation:

y varies inversely with x setup is:

y = k/x

7 = \frac{k}{2/3}  (find 'k')

k = 7/1 · 2/3

k = 14/3

use what you know about 'k' and 'x' to solve for 'y'

y = 14/3 ÷ 7/3  (remember to multiply by the reciprocal when dividing fractions)

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Tems11 [23]

Answer:

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hope that answers your question

Don't hesitate to leave a comment if you are confused about something

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
HELP PLEASE!! EXTRA POINTS AND BRAINLIEST WILL BE GIVEN!!
mezya [45]

Answer:

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Step-by-step explanation:

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RideAnS [48]

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Step-by-step explanation:

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Step-by-step explanation:

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