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Oksi-84 [34.3K]
3 years ago
11

Which value, when placed in the box, would result in a system of equations with infinitely many solutions?

Mathematics
2 answers:
hoa [83]3 years ago
8 0

Answer:

-10

Step-by-step explanation:

ira [324]3 years ago
7 0
<span>For a system of equations to have infinitely many solutions, the equations have to be lineary dependent, (i.e. one of the equations is a multiple of the other equation). For the given equation to have infinitely many solutions, the second equation have to be a multiple of the first equation. The first equation can be rewritten as y - 2x = -5 The second equation is the first equation multiplied by 2, i.e. 2(y - 2x= -5) = 2y - 4x = -10 Therefore, the correct answer is -10 (option a).</span>
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RSB [31]
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Step-by-step explanation:

We have,

y = (3x + x^2)^5          ..... (1)

To find, \dfrac{dy}{dx} = ?

Differentiating equation (1) w.r.t. 'x', we get

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