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3 years ago

HELPPO ME PLEASEE!!!!!!

Mathematics

1 answer:

ElenaW [278]3 years ago

4 0

Answer:

Here,

x + 25° + 3x + 95° + 80°=360° (Sum of angles of a quadrilateral is 360°)

or,x+3x + 25° + 95° + 80° =360°

or,4x + 200 = 360°

or,4x = 360 - 200

or,4x = 160

or,x = 160÷4

or,x = 40

Now,

Angle K = (x + 25)° = 40 + 25° = 65°

Angle L = 3x° = 3 × 40° = 120°

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Which of the following is a polynomial with roots 3, 5i, and −5i?

jek_recluse [69]

$x_{1}=3 \\ \\ x_{2}=5i \\ \\ x_{2}=-5i \\ \\ f(x)=(x-x_{1})(x-x_{2})(x-x_{3})=(x-3)(x-5i)(x+5i)= \\ \\ =(x-3)(x^{2}+25)=x^{3}+25x-3x^{2}-75=x^{3}-3x^{2}+25x-75$

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6 0

3 years ago

Find the tangent plane to the given surface of f(x,y)=6- 6/5 x-y at the point (5, -1, 1). Make sure tat your final answer for th

HACTEHA [7]

Answer:

Required equation of tangent plane is $z=\frac{6}{5}(x-5y-11)$ .

Step-by-step explanation:

Given surface function is,

$f(x,y)=6-\frac{6}{5}(x-y)$

To find tangent plane at the point (5,-1,1).

We know equation of tangent plane at the point $(x_0,y_0,z_0)[/tex] is,

$z=f(x_0,y_0)+f_x(x_0,y_0)(x-x_0)+f_y(x_0,y_0)(y-y_0)\hfill (1)$

So that,

$f(x_0,y_0)=6-\frac{6}{5}(5+1)=-\frac{6}{5}$

$f_x=-\frac{6}{5}y\implies f_x(5,-1,1)=\frac{6}{5}$

$f_y=-\frac{6}{5}x\implies f_y(5,-1,1)=-6$

Substitute all these values in (1) we get,

$z=\frac{6}{5}(x-5)-6(y+1)-\frac{6}{5}$

$\therefore z=\frac{6}{5}(x-5y-11)$

Which is the required euation of tangent plane.

4 0

3 years ago

Simplify. If d = –3, evaluate –d. –3 1 0 3

AnnZ [28]

-d would equal 3. just flip its around right?

7 0

3 years ago

Write the equation of the line that passes through the points (-7, -9) and (7,2)

aksik [14]

Step-by-step explanation:

-8 and 8

These numbers are only through the two numbers.

8 0

3 years ago

Cara grew 4 inches in a second grade and 3in in a third grade. If cara was 44 inches tall at the start of second grade, how tall

ivann1987 [24]

Answer:

51 inches (or 4 feet 2 inches)

Step-by-step explanation:

if she was 44 inches at the start of second grade, grew 4 inches through second, then grew 3 more inches through third grade, she would be 51 inches (Or 4 feet 2 inches)

5 0

3 years ago