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Komok [63]
3 years ago
7

What is value of x for which the equation 9^-6 x 9^x = 1

Mathematics
2 answers:
kipiarov [429]3 years ago
4 0

Answer:

x=6

Step-by-step explanation:

9^-6*9^x=1

(x-6)In(9)=In(1)

Awnser

x=6

miskamm [114]3 years ago
3 0
X=6 I hope this helps you out
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10 points to the person who answers this whole thing and I will mark you as brainliest.
olga2289 [7]

Answer:

Step-by-step explanation:

Perimeter is found by adding together all the lengths of the sides. For us, that is x + (2x + 5) + (6x - 17) + (3x + 2). Now we will just combine like terms. We can also drop the parenthesis because they do nothing for us and mean nothing to the problem.

x + 2x + 5 + 6x - 17 + 3x + 2 becomes

12x - 10

4 0
3 years ago
Solve the differential equation y prime equals the product of 2 times x and the square root of the quantity 1 minus y squared .
MatroZZZ [7]

Answer:

1. y = sin(x²+C)

2. see below

Step-by-step explanation:

1. \frac{dy}{dx} = 2x\sqrt{1-y^2}

separation of variables

\frac{dy}{\sqrt{1-y^2} } = 2xdx

integration both sides\int\frac{dy}{\sqrt{1-y^2} } = \int2xdx

you should get :

sin^{-1} (y) = x^2+C remember constant of integration!!

2. y = sin(x²+C)

3 = sin(0+C)

y(0) = 3 does not have a solution because our sin graph is not shifted vertically or multiplied by a factor whose absolute value is greater than 1, so our range is [-1,1] and 3 is not part of this range

4 0
3 years ago
a coin collector has 36 dimes and nickels with a total face value of $2.80. they are actually worth a lot more. how many of each
Juliette [100K]

Answer:

16 nickels and 20 dimes

Step-by-step explanation:

16x5=80

20x10=200

80+200=280

280 cents = $2.80

8 0
3 years ago
How do I find The measure of ML
svlad2 [7]
When two chords<span> intersect inside a circle, the product of the two segments of one </span>chord<span> equals the product of the two segments of the other chord.
</span><span>MN*NL=KN*LN
10x=4*20=80
x=8
ML=MN+NL=18


<span /></span>
4 0
3 years ago
Lim x-1 x2 - 1/ sin(x-2)
balu736 [363]

Answer:

           \lim_{x \to 1}\frac{x^2-1}{sin(x-2)}=0

Explanation:

Assuming the correct expression is to find the following limit:

         \lim_{x \to 1}\frac{x^2-1}{sin(x-2)}

Use the property the limit of the quotient is the quotient of the limits:

         \lim_{x \to 1}\frac{x^2-1}{sin(x-2)}=\frac{\lim_{x \to 1}x^2-1}{\lim_{x \to 1}sin(x-2)}

Evaluate the numerator:

          \frac{\lim_{x \to 1}x^2-1}{\lim_{x \to 1}sin(x-2)}=\frac{1^2-1}{\lim_{x \to1}sin(x-2)}=\frac{0}{\lim_{x \to 1}sin(x-2}

Evaluate the denominator:

  • Since         \lim_{x \to1}sin(x-2)\neq 0

                  \frac{0}{\lim_{x \to1}sin(x-2)}=0

4 0
2 years ago
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