So what you do is
make into ax^2+bx+c=0 form
add-9/2 to both sides
y^2-2y+9/2=0
now we use the quadratice formula which is
x=
ax^2+bx+c=0
1y^2-2y+9/2
a=1
b=-2
c=9/2
subsitute
x=
x=
x=
x=
x=
x=
x=
x=
x=
answer is C
Answer:
I think it is 6/7
Step-by-step explanation:
I am really bad at explaining but I'm not completely sure
Answer:
y=x^28x+31
Step-by-step explanation:
If the point U is between points T and V, then the numerical length of TV is 29 units
<h3>How to determine the numerical length of segment TV?</h3>
From the question, we have the following lengths that can be used in our computation:
- Length TU = 18 units
- Length UV = 11 units
The above parameters and representations implies that the point U is between endpoints T and V
This also means that the length TV is longer than the other lengths TU and TV
So, we have the following length equation
TV = TU + UV
Substitute the known values in the above equation
So, we have the following equation
TV = 18 + 11
Evaluate the sum of the like terms in the above equation
So, we have the following equation
TV = 29
Hence, the numerical length of segment TV is 29 units
Read more about lengths at
brainly.com/question/19131183
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<u>Possible question</u>
If tu = 18 and uv = 11 what is tv, if point u is between points t and v
Answer:
Step-by-step explanation:
