We can readily know the x^2-4x+4=3y then use it to replace the same function in the first equation which refers to the 3y+y^2-6y=0
y^2-3y=0
y(y-3)=0
y1=0 -----------y2=3
Use photomath it will also help
(-4 1/2) / (-2 2/3) =.....turn to improper fractions
(- 9/2) / (-8/3) =...when dividing fractions, flip what u r dividing by, then multiply
-9/2 * -3/8 =
27/16 =
1 11/16 <==
Answer:
20x + 28y
Step-by-step explanation:
