Answer:
1. -7.5
2. $1
3. 40
Step-by-step explanation:
For number 1, it can be solved by using the PEMDAS method, or see explanation below:
6x - 4x - 36 = 6 - 2x
2x - 36= -2x + 6
4x + 36 = 6
4x = -30
x = -15/2 or -7.5
For number 2, substitute 3 into both equations:
f(x) =1.50(3) + 2.00
and
f(x) = 2.00(3) + 1.50
This would get $6.50 and $7.50, which, if subtracted, gets $1.
For number 3, do something similar to the previous problem. Substitute 3 for x. It would be 5(2^3), or 40.
Hope this helps!
Answer:
log(32/125)
=log32 - log125 [log(x/y)=log(x) - log(y)]
=log(2)^2 - log(5)^3
=2log2-3log5 [log(x)^p=p log x]
=2a-3b
Answer:
(B) i think
Step-by-step explanation:
comment how it help
Answer:
Area of the rhombus, A = 22.5 sq. ft.
Step-by-step explanation:
The area of a rhombus = a. b
where, a = side of the rhombus
and b = height of the rhombus.
Here, the side, a = 5 ft
Height, b = 4.5 ft.
Therefore, area, A = 5 X 4.5 sq. ft
⇒ A = 22.5 sq. ft which is the required answer.
You could subtract the denominator fro the numerator which would give you a total sum of 1 thousand an fifty five
