WILL GIVE BRAINLIEST help me with this question pls:)

HELP!

wariber [46]

Answer: 50w+150>650

w>10

Step-by-step explanation: Subtract 150 on both sides, leaving 50w>500. Divide both sides by 50 to get w>10

3 0

3 years ago

BRAINLIEST TO WHOEVER CAN HELP ME !!Select the correct statement about the function represented by the table.

Paha777 [63]

B would be the answer

7 0

3 years ago

Find the lowest common denominator of and . A. (p + 2) B. (p + 5)(p + 3) C. (p + 5)(p + 2)(p + 3) D. (p + 2)2

laiz [17]

The lowest (or least) common denominator also written as LCD is the smallest of all the possible common denominators, where the denominator is the bottom number in a fraction.
We should find the lowest common denominator of (p+3)/(p^2+7p+10) and (p+5)/(p^2+5p+6).
p^2+7p+10 can be written as a product: (p+5)(p+2)
p^2+5p+6 can be written as a product: (p+3)(p+2)
So, we should find the LCD for (p+5)(p+2) and (p+3)(p+2). The smallest possible number that can be divided with both of them is:(p + 5)(p + 2)(p + 3)
Solution C.

6 0

3 years ago

I need help please, I am so confused.

vazorg [7]

Answer:

$\begin{tabular}{| c | c | c |}\cline{1-3} Equation & x-intercepts & x-coordinate of vertex\\\cline{1-3} $y=x(x-2)$ & $x=0, x=2$ & $x=1$\\\cline{1-3} $y=(x-4)(x+5)$ & $x=-5, x=4$ & $x=-0.5$\\\cline{1-3} $y=-5x(x-3)$ & $x=0, x=3$ & $x=1.5$\\\cline{1-3} \end{tabular}$

Step-by-step explanation:

x-intercepts are when the curve intercepts the x-axis, so when y =0.

Therefore, to find the x-intercepts, substitute y = 0 and solve for x.

The vertex is the turning point: the minimum point of a parabola that opens upward, and the maximum point of the parabola that opens downward. As a parabola is symmetrical, the x-coordinate of the vertex is the midpoint of the x-intercepts.

Equation: $y=x(x-2)$

$\implies x(x-2)=0$

$\implies x=0$

$\implies (x-2)=0 \implies x=2$

Therefore, the x-intercepts are x = 0 and x = 2

The midpoint of the x-intercepts is x = 1, so the x-coordinate of the vertex is x = 1

Equation: $y=(x-4)(x+5)$

$\implies (x-4)(x+5)=0$

$\implies (x-4)=0 \implies x=4$

$\implies (x+5)=0 \implies x=-5$

Therefore, the x-intercepts are x = -5 and x = 4

The midpoint of the x-intercepts is x = -0.5, so the x-coordinate of the vertex is x = -0.5

Equation: $y=-5x(3-x)$

$\implies -5x(3-x)=0$

$\implies -5x=0 \implies x=0$

$\implies (3-x)=0 \implies x=3$

Therefore, the x-intercepts are x = 0 and x = 3

The midpoint of the x-intercepts is x = 1.5, so the x-coordinate of the vertex is x = 1.5

$\begin{tabular}{| c | c | c |}\cline{1-3} Equation & x-intercepts & x-coordinate of vertex\\\cline{1-3} $y=x(x-2)$ & $x=0, x=2$ & $x=1$\\\cline{1-3} $y=(x-4)(x+5)$ & $x=-5, x=4$ & $x=-0.5$\\\cline{1-3} $y=-5x(x-3)$ & $x=0, x=3$ & $x=1.5$\\\cline{1-3} \end{tabular}$

4 0

2 years ago

What is the quotient of

Komok [63]

Answer:The exact form is -10/7 the simplified form is -1 3/7

Step-by-step explanation:

3 0

3 years ago

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