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Drupady [299]
3 years ago
12

HELP ALGEBRA IF YOU KNOW THIS PLS HELPPP

Mathematics
1 answer:
professor190 [17]3 years ago
6 0

Answer:

I think its third answer..24=w*+5w

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Factor the polynomial expression x4 – 6x2 + 5.
Serga [27]

Answer:

Hello!

______________________

x4 – 6x2 + 5

= ( x^2 - 5) ( x + 1 ) ( x - 1 )

Step-by-step explanation: Factor.

Hope this helped you!

4 0
3 years ago
a father is 27 years older than his son. ten years ago he was twice as old as his son. how old is the father​
Vika [28.1K]

Answer:

44?

Step-by-step explanation:

27-10=17

17+27=44

4 0
3 years ago
solve this system of linear equations. separate the x- and y-values with a comma. x = -42 - 8y -18x = -4 - 8y
just olya [345]

Answer:

x= -19/9

y= -17/72


7 0
3 years ago
4. Builtrite D is considering the purchase of a new machine for $500,000 which would require a $5000 installation charge. Employ
Paraphin [41]

Answer:

Builtrite D should purchase the machine

Step-by-step explanation:

Cash outflow in year zero = $ 500,000 + $ 25,000 ( training cost ) + $ 30,000 ( Net working capital)

Cash outflow in year zero = $ 555,000

Terminal cash flow in year 10  = $ 150,000 + $ 30,000 ( NWC)

Terminal cash flow in year 10  = $ 180,000

Operating cash flow per year = [ Savings - expenses - depreciation ] X ( 1 - tax rate) + depreciation

Net present value = -500,000 + \frac{116,000}{1.15^1} + \frac{116,000}{1.15^2} +...+ \frac{180,000}{1.15^{10}}

The Net present value of purchasing the machine = $32,071.42

Builtrite D should purchase the machine

3 0
3 years ago
Which equation of the line written in standard form has has a slope of 6 and contains the points (-1,-3)
11Alexandr11 [23.1K]

keeping in mind that standard form for a linear equation means

• all coefficients must be integers, no fractions

• only the constant on the right-hand-side

• all variables on the left-hand-side, sorted

• "x" must not have a negative coefficient

\bf (\stackrel{x_1}{-1}~,~\stackrel{y_1}{-3})~\hspace{10em} slope = m\implies 6 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-(-3)=6[x-(-1)]\implies y+3=6(x+1) \\\\\\ y+3=6x+6\implies y=6x+3\implies -6x+y=3\implies 6x-y=-3

5 0
3 years ago
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