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3 years ago

Write the mixed number as an improper fraction 13/5

2 answers:

8 0

13/5 is already improper. To change to a mixed number you’d ask how many times 5 goes into 13 and how many you’d have left over.

2 and 3/5

Advocard [28]3 years ago

6 0

Answer:

8/5

Step-by-step explanation:

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A paper company produces 3,580 notebooks in 4 days. How many notebooks can it produce in 12 days?

RoseWind [281]

10,740

Step-by-step explanation:

multiply by 3, because 4 x 3 equals 12, so that infers 3580 x 3, which equals 10,740

7 0

3 years ago

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Can 1 2/88 be simplified any lower?

pochemuha

Yes. It can be simplified into 1 1/44

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3 years ago

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Analyze the graph of the given polar curve. If possible, describe the shape of the graph (circle,rose curve, limacon, etc), and

Darya [45]

Rose petal with 5 petals

Domain: all real numbers

Range: [-2,2]

Symmetric about the x-axis

Continuous

Bounded

Maximum r-value: 2

No asymptotes

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3 years ago

Shelly paid $8.84 for a pizza. This amount includes a sales tax of 4%. What was the cost of the pizza before tax?

lorasvet [3.4K]

Answer:

$8.50

Step-by-step explanation:

let the price before tax be $x

given that the sales tax rate is 4%, hence the amount she paid in taxes

= 4% of x

= (4/100)x

= 0.04x

We can now build an equation for what she paid:

Amount Paid = price before tax + amount paid in taxes

8.84 = x + 0.04x

8.84 = 1.04x (divide both sides by 1.04 and rearranging)

x = 8.84 / 1.04

x = $8.50

7 0

3 years ago

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Write an equation for an ellipse centered at the origin, which has foci at (\pm5,0)(±5,0)(, plus minus, 5, comma, 0, )and vertic

Virty [35]

Answer:

The equation of ellipse is

$\frac{x^2}{41}+\frac{y^2}{16}=1$

Step-by-step explanation:

The equation of an ellipse is

$\frac{(x-h)^2}{a^2}+\frac{(y-k)^2}{b^2}=1$

where(h,k) is the center and c is distance from the center to the foci is given by $a^2-b^2=c^2$ . a is the distance from the center to the vertices and b is the distance from the center to the co-vertices.

The center of the ellipse is the mid-point of the vertices.

The mid point of the vertices $(\pm\sqrt{41},0)$ is

= $(\frac{\sqrt{41}+(-\sqr{41})}2,\frac{0+0}2)$

=(0,0)

a is the distance between the center and the vertices.

So, $a=\sqrt{(0-\sqrt{41})^2+(0-0)^2}$

$=\sqrt{41}$

c is the distance between the center and the foci.

So, $c=\sqrt{(0-5)^2+(0-0)^2$

$a^2-b^2=c^2$

$\Rightarrow (\sqrt41)^2-b^2=5^2$

$\Rightarrow b^2=(\sqrt41)^2- 5^2$

$\Rightarrow b^2=41-25$

$\Rightarrow b^2=16$

The equation of ellipse is

$\frac{(x-0)^2}{(\sqrt{41})^2}+\frac{(y-0)^2}{16}=1$

$\Rightarrow \frac{x^2}{41}+\frac{y^2}{16}=1$

7 0

4 years ago