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stich3 [128]
3 years ago
12

Write the mixed number as an improper fraction 13/5

Mathematics
2 answers:
Viktor [21]3 years ago
8 0
13/5 is already improper. To change to a mixed number you’d ask how many times 5 goes into 13 and how many you’d have left over.

2 and 3/5
Advocard [28]3 years ago
6 0

Answer:

8/5

Step-by-step explanation:

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The projected worth (in millions of dollars) of a large company is modeled by the equation w = 236(1.06) t. The variable t repre
Ivahew [28]

Answer:

$448 million

Step-by-step explanation:

When it is 2011, t=11, so

w=236(1.06)^{11} \approx 448

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1 year ago
What is the equation of the line that passes through the point (6, 8) and has a slope 1/2
Korvikt [17]

Answer:

y=1/2x+5

Step-by-step explanation:

Plug it into the formula for a point and a slope.

(y-(y(subscript 1)))=(m)(x-(x(subscript 1)))

Y-8=1/2(x-6)

Then multiply the 1/2 to the x and -6. After you do that, move everything so that it has y by itself on the left. Your ending should be y=1/2x+5.

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2 years ago
Suppose the x-axis of a density graph represents someone's height in inches. If the area under the density curve from 60 inches
masha68 [24]

OPTION A 75% is the correct answer

6 0
2 years ago
The distance of a golf ball from the hole can be represented by the right side of a parabola with vertex (-1,8). The ball reache
ddd [48]

Answer:

Let's suppose that the hole is at y = 0m, where x is the time variable.

we know that:

The vertex is (-1s, 8m).

(i suppose x in seconds and y in meters)

At x = 1s, the ball reaches the hole, so we also have the point:

(1s, 0m).

Remember that the vertex of a quadratic equation y = a*x^2 + b*x + c is at:

x = -b/2a,

then we have:

-1 = -b/2a.

Then we have tree equations:

8m = a*(-1s)^2 + b*-1s + c

0m = a*(1s)^2 + b*1s + c

-1s = -b/2a.

First we should isolate one variable in the third equation, and then replace it in one of the other two:

1s*2a = b.

So we can replace b in the first two equations bi 1s*2a.

8m = a*1s^2 - 1s*2a*1s + c

0m = a*1s^2 + 1s*2a*1s + c

We can simplify both equations and get:

8m = a*( 1s^2 - 2s^2) + c = -a*1s^2 + c.

0m = a*(1s^2 + 2s^2) + c = a*3s^2 + c.

Easily we can isolate c in the second equation and then replace it into the first equation:

c = -a*3s^2

The first equation becomes:

8m = -a*1s^2 - a*3s^2 = -a*4s^2

a = 8m/-4s^2 = -2m/s^2.

Now with a, we can find the values of c and b.

c = -a*3s^2 = -(-2m/s^2)*3s^2 = 6m.

b = 1s*2a = 1s*(-2m/s^2) = -2m/s.

Then the equation is:

y = (-2m/s^2)*t^2 + (-2m/s)*t + 6m

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Answer:

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