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trasher [3.6K]
2 years ago
13

10 = 3c − 2 c = what

Mathematics
1 answer:
creativ13 [48]2 years ago
4 0

Answer:

Step-by-step explanation:

Here you go mate

Step 1

10=3c-2  Equation/Question

Step 2

10=3c-2  Simplify

10=3c-2

Step 3

10=3c-2  Add +2

3c=12

Step 4

3c=12  Then you divide the exponents by 3

answer

c=4

Hope this helps

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Find the product: 377(10, 000).
Illusion [34]

Answer:

37, 700, 000

Step-by-step explanation:

377(10,000) = 377 x 10,000

= 37, 700, 000

an easy way to see it is to just add the number of zeros from 10,000 to 377. since there are four zeros, you put four zeros behind 377.

<em><u>[it's not mathematical but it helps u see the answer better. and it only works with numbers that start with 1]</u></em>

7 0
3 years ago
Please help I’ll give brainliest
Bingel [31]

Answer:  A, 4^4

Step-by-step explanation:

4^7/4^3 = 4^4

5 0
2 years ago
Read 2 more answers
Shureka Washburn has scores of 67​, 68​, 76​, and 63 on her algebra tests. a. Use an inequality to find the scores she must make
mash [69]
Average=(total number)/(number of items)
given that the final exam counts as two test, let the final exam be x. The weight of the final exams on the average is 2, thus the final exam can be written as 2x because any score Shureka gets will be doubled before the averaging.
Hence our inequality will be as follows:
(67+68+76+63+2x)/6≥71
(274+2x)/6≥71
solving the above we get:
274+2x≥71×6
274+2x≥426
2x≥426-274
2x≥152
x≥76

b] The above answer is x≥76, the mean of this is that if Shureka is aiming at getting an average of 71 or above, then she should be able to get a minimum score of 76 or above. Anything less than 76 will drop her average lower than 71.


8 0
3 years ago
(DESPERATE PLEASE HURRY)<br> question down below<br> please show the work
zubka84 [21]

Answer:

v= -12

Step-by-step explanation:

v= -12

v = -29+17

v= -12

3 0
2 years ago
Read 2 more answers
Simplify fully e x e x e x f/ e x e x f x f
mel-nik [20]

Given:

The given expression is

\dfrac{e\times e\times e\times f}{e\times e\times f\times f}

To find:

The simplified form of given expression.

Solution:

We have,

\dfrac{e\times e\times e\times f}{e\times e\times f\times f}

The common factors in numerator and denominator are e, e, f.

Cancel out the common factors.

=\dfrac{e}{f}

Therefore, the required expression is \dfrac{e}{f}.

6 0
2 years ago
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