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kow [346]
3 years ago
9

The values square root of 12 and square root of 15 or put it on the number line what is the approximate difference in tents betw

een square root of 12 and square root of 15
Mathematics
1 answer:
Murrr4er [49]3 years ago
7 0

Answer:

Square root of 12 = 3.46410161514

Square root of 15 = 3.87298334621

Difference = .3219671948

Step-by-step explanation:

Put it on a number line and that should be ur answer, also plz mark brainliest.

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List the sides in order from shortest to longest. The diagram is not to scale. Triangle upper J upper K upper L is shown. Angle
aniked [119]

Answer:

your answer would be C

Step-by-step explanation:

line segment JK,Modifying above upper L upper J with bar, Modifying above Upper L Upper K with bar

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3 years ago
Titus works at a hotel. Part of his job is to keep the complimentary pitcher of water at least half full and always with ice. Wh
stira [4]

Answer:

according to the equation it is 158.330917...

Step-by-step explanation:

put w as 64 and solve for t

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3 years ago
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karen wants to find the area of the isosceles triangle ABC. she knows that the base of the triangle (side CB) is equal to 8 squa
S_A_V [24]

Answer:

16 squares

Step-by-step explanation:

The area of an isosceles is \frac{bh}{2}

8 \cdot 4 = 32\\32 \div 2 = 16

Hope this helped!

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3 years ago
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The measure on angle 0 is 7pie/4. Measure of its reference angle is __ °, and the tan 0 is ___
soldier1979 [14.2K]

Answer:

Reference angle is \frac{\pi }{4} and tan\frac{7\pi }{4} = -1

Step-by-step explanation:

\frac{7\pi }{4} lies in the 4th quadrant

and reference angle for angle in 4th quadrant is 2π - x , where x is the angle given.


and reference angle for \frac{7\pi }{4} is  

2π-\frac{7\pi }{4} = \frac{\pi }{4}

and tan\frac{7\pi }{4} = -tan \frac{\pi }{4}=  -1

Since tan is negative in 4th quadrant ,therefore value will be  negative for the given angle.


7 0
3 years ago
The diagram shows the curve with equation y = ( 1 + x ) cosx.
r-ruslan [8.4K]

Answer:

y = 1, 1.319, 1.024, 0

Step-by-step explanation:

Given equation:

y=(1+x)\cos x

\textsf{when}\:x=0:

\begin{aligned} \implies y & =(1+0)\cos 0\\\implies y & = 1\end{aligned}

\textsf{when}\:x=\dfrac{\pi}{6}:

\begin{aligned} \implies y & =\left(1+\frac{\pi}{6}\right)\cos \left(\frac{\pi}{6}\right)\\\implies y & = 1.319\: \sf (3\:dp)\end{aligned}

\textsf{when}\:x=\dfrac{\pi}{3}:

\begin{aligned} \implies y & =\left(1+\frac{\pi}{3}\right)\cos \left(\frac{\pi}{3}\right)\\\implies y & = 1.024\: \sf (3\:dp)\end{aligned}

\textsf{when}\:x=\dfrac{\pi}{2}:

\begin{aligned} \implies y & =\left(1+\frac{\pi}{2}\right)\cos \left(\frac{\pi}{2}\right)\\\implies y & = 0\end{aligned}

8 0
2 years ago
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