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kow [346]
3 years ago
9

The values square root of 12 and square root of 15 or put it on the number line what is the approximate difference in tents betw

een square root of 12 and square root of 15
Mathematics
1 answer:
Murrr4er [49]3 years ago
7 0

Answer:

Square root of 12 = 3.46410161514

Square root of 15 = 3.87298334621

Difference = .3219671948

Step-by-step explanation:

Put it on a number line and that should be ur answer, also plz mark brainliest.

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Eva8 [605]
I'm not 100% sure that this is correct but it's a 50 50

The first one is none of these

Second one is alternate interior (I am 100% sure on this one)

Third one is corresponding

Fourth one is alternate exterior (also 100% sure)

Fifth one is also corresponding

I tried my best

7 0
4 years ago
Read 2 more answers
The length and width of a rectangle are measured as 30cm and 24cm, respectively, with an error in measured of
larisa [96]

Answer:

The maximum error in the calculated area of rectangle is 5.4 cm².

Step-by-step explanation:

Given : The length and width of a rectangle are measured as 30 cm and 24 cm, respectively, with an error in measured of  at most 0.1 cm in each.

To find : Use differentials to estimate the maximum error in the calculated area of rectangle ?

Solution :

The area of the rectangle is A=l\times w

The derivative of the area is equal to the partial derivative of area w.r.t. length times the change in length plus the partial derivative of area w.r.t. width times the change in width.

i.e. dA=\frac{\partial A}{\partial L}\Delta L+\frac{\partial A}{\partial W}\Delta W

Here, \frac{\partial A}{\partial L}=30,\ \frac{\partial A}{\partial W}=24 ,\ \Delta L=0.1,\ \Delta W=0.1

Substitute the values,

dA=(30)(0.1)+(24)(0.1)

dA=3+2.4

dA=5.4

Therefore, the maximum error in the calculated area of rectangle is 5.4 cm².

7 0
3 years ago
Which of the following shapes is the cross-section for a cylinder?
Step2247 [10]

The cross-section of a cylinder is in the shape of a Circle

5 0
3 years ago
A large cable company reports the following.
Oduvanchick [21]

Answer:

Step-by-step explanation:

Let n(U) be total amount or customers = 100%

n(C) = 80% of its customers subscribe to its cable TV service.

n(I) = 41% of its customers subscribe to its Internet service.

n(T) = 31% of its customers subscribe to its telephone service.

n(CnI) = 25% of its customers subscribe to both its cable TV and Internet service.

n(CnT) = 20% of its customers subscribe to both its cable TV and phone service.

n(InT) = 22% of its customers subscribe to both its Internet and phone service.

n(CnInT) = 15% of its customers subscribe to all three services

number of those that subscribed to TV only = n(C) - (n(CnInT')+(n(CnI'nT)+(n(CnInT))

= 80-[(25-15)+(20-15)+15]

= 80-{10+5+15)

= 80-30

= 50

Hence 50% read cable TV only

Pr(cable TV only) = 50/100 = 1/2

2) number of people that read internet and cable TV = 25%

Pr(internet and cable) = 25/100 = 1/4

3) number of people that had exactly two services are;

n(cable and internet only)+n(internet and phone only)+(cable and phone only)

= (25-15)+(22-15)+(20-15)

= 10+7+4

= 21%

Hence 21℅ read exactly two services

pr(exactly 2 services) = 21/100

4) number of people that read internet and cable only = n(CnI) - n(CnInP)

= 25-15 = 10%

Pr(Internet and cable only) = 10/100 = 1/10

8 0
3 years ago
Help please!
givi [52]
4 is the answer :) I hope you
6 0
3 years ago
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