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liberstina [14]
3 years ago
13

What are the roots of the polynomial equation x3 - 6x= 3x2 - 8? Use a graphing calculator and a system of equations

Mathematics
1 answer:
lesya [120]3 years ago
4 0

Answer:

Hence, the roots of the polynomial equation are:

-2, 1, 4

Step-by-step explanation:

We are asked to find the roots of the polynomial equation:

We can also equate this equation to y to obtain a system of equation as:

and

Hence, the roots of the polynomial; equation are the x-values of the point of intersections of the graph of the system of equations.

Hence, the point of intersection of the two graphs are:

(-2,4), (1,-5) and (4,40)

Hence, the roots of the polynomial equation are:

-2, 1, 4

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Solve for X by multiplying both sides by 9:

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6 0
3 years ago
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From the given sides of 16, 14, and 21, determine what type of triangle it will form (right, acute, obtuse, none).
Komok [63]

Answer:

It is an acute triangle.

Step-by-step explanation:

It would be much easier for you to see where I'm getting at if you draw a diagram.

Assume this triangle is labelled ABC where a = 14, b = 21, and c = 16.

cos A = (16^2 + 21^2 - 14^2)/(2(16)(21))

∠A = cos^-1(0.82291...)

∠A ≅ 34.6°

cos B = 16^2 + 14^2 - 21^2)/(2(16)(14))

∠B = cos^-1(0.024...)

∠B ≅ 56.8°

∠C = 180 - (∠A + ∠B)

∠C ≅ 56.8°

Since there is no right-angle nor is there an obtuse angle,

Therefore the triangle is an acute triangle.

4 0
3 years ago
Need help on this question 36
frosja888 [35]
For the bottom, to find the top side of the triangle, 10-4, as seen from the top and bottom sides of the rectangle. So 6.

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Now that we have 6 and 4, we can find the area:

A= ab/2

A= (6*4)/2

A=24/2

A=12 mm^2
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