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Lena [83]
3 years ago
10

5. Calculate how long in seconds it will take for a light pulse to travel from earth to the moon. The distance from earth to moo

n is 3.84 x 105 km. Remember that light travels at 186,000 mi/s. (4 pts)
Physics
1 answer:
solniwko [45]3 years ago
3 0

Answer:

0.13 seconds

Explanation:

Since 1 Km = 0.621 miles

3.84 x 105 km = 3.84 x 105 × 0.621 = 23846.4 miles

Speed = distance/time

time= distance/speed

Time= 23846.4/186,000

Time= 0.13 seconds

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An electric circuit where electrons are free to flow
maw [93]

Answer: Electron flow / Electric current

7 0
3 years ago
Which describes the relationship between potential and kinetic energy of a ball thrown up in the air as it falls back to the gro
Gekata [30.6K]
The answer is c, because ball is falling so its gravitationl potential energy decreases, but it kinetic energy increases. Energy is always conserved.
7 0
3 years ago
The hour and minute hands of a tower clock like Big Ben in London are 2.79 m and 4.44 m long and have masses of 58.2 kg and 90 k
LuckyWell [14K]

Answer: 895.85 x 10^-6 J or 8.96 x 10^-4 J

Explanation:

Angular kinetic energy E in Joules

E = ½Iw^2

W is angular velocity in radians/sec

1 radian/sec = 9.55 rev/min

I is moment of inertia in kgm^2

I = cMR^2

M is mass (kg), R is radius (meters)

c = 1/3 for a rod around its end, R = length

For minute hand

I = (1/3)(90)(4.44)^2 = 0.33 x 90 x 19.7136 = 585.49

w= 1 rev/hour = 1 rev/3600sec = 2pi/ 3600 = pi/1800 rad/s

KE = 1/2(1/3)(90)(4.44)^2(pi/1800)^2 = 0.5 x 0.33 x 90 x 19.7136 x 3.05 x 10^-6

KE = 0.00089 J

For hour hand

I = (1/3)(58.2)(2.79)^2 = 0.33 x 58.2 x 2.79^2 = 149.5

w = 1 rev/12hour = 1 rev/(12x3600sec) = 2pi/ 12x3600 = pi/21600 rad/s

KE = 1/2(1/3)(90)(4.44)^2(pi/21600)^2 = 0.5 x 0.33 x 90 x 19.7136 x 2.12 x 10^-8

KE = 5.85 x 10^-6 J

Therefore total kinetic energy = 895.85 x 10^-6 J

4 0
4 years ago
Problem 10.32
Mashcka [7]

Answer : \alpha = -240\ rad/s^{2} south

Explanation :

Given that,

Force = 200 N

Length = 2.00 m

Mass = 5.00 kg

We know that , the  formula of the angular acceleration

\alpha = \dfrac{\tau}{I}\ rad/s^{2}

We know the moment of inertia of rod

I = \dfrac{ML^{2}}{12}

Now, the torque is

\tau = F\times r

The angular acceleration

\alpha = \dfrac{F\times r\times12}{ML^{2}}

\alpha = \dfrac{((200\ N\times-1\ m) + (-200\ N)\times(1\ m))\times12}{5\ kg\times2\ m\times2\ m}

\alpha = \dfrac{-400Nm\times12}{5kg\times4m^{2}}

\alpha = -240\ rad/s^{2}  

Negative sign represent of south direction.    

Hence, this is the required solution.


7 0
4 years ago
Read 2 more answers
Power is the time rate of change of work. <br> a. True<br> b. False
Bumek [7]
The statement about "<span>Power is the time rate of change of work" is true. The answer is letter A. Power is presented by the equation P = Wt where P is the power, W is work and t is time.</span>
6 0
4 years ago
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