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jeka94
2 years ago
12

Now, let's look at how the distance from the charge affects the magnitude of the electric field. Select Values on the menu, and

then click and drag one of the yellow E-Field Sensors. You will see the magnitude of the electric field given in units of V/m (volts per meter, which is the same as newtons per coulomb). Place the E-Field Sensor 1 m away from the positive charge (1 m is two bold grid lines away if going in a horizontal or vertical direction), and look at the resulting field strength. Consider the locations to the right, left, above, and below the positive charge, all 1 m away. For these four locations, the magnitude of the electric field is________________. the same. greatest to the left of the charge. greatest below the charge. greatest to the right of the charge. greatest above the charge.
Physics
1 answer:
marin [14]2 years ago
6 0

Electric field strength decreases as the distance from the source increases.

<h3>How the distance from the charge affects the magnitude of the electric field?</h3>

The strength of an electric field is inversely related to square of the distance from the source. This means that the electric field strength decreases when the distance from the source increases.

So we can conclude that Electric field strength decreases as the distance from the source increases.

Learn more about source here: brainly.com/question/25578076

#SPJ9

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Why is the ionic compound magnesium chloride neutral
shutvik [7]

Answer: The charges on cation and anion balances each other.

Explanation:

For formation of a neutral ionic compound, the charges on cation and anion must be balanced. The cation is formed by loss of electrons by metals and anions are formed by gain of electrons by non metals.  

Mg:12:1s^22s^22p^63s^2

Mg^{2+}:10:1s^22s^22p^6

Cl:17:1s^22s^22p^63s^23p^5

Cl^{-}:18:1s^22s^22p^63s^23p^6

Thus Mg^{2+} combines with two Cl^- ions to give neutral MgCl_2

8 0
3 years ago
Does anyone know the answer to this?
sweet-ann [11.9K]
Disclaimer: I just answered this, here is the answer again!
*Used copy paste from my own answer as it is a repeated question, no copied work*

3. A
The relation between V and I at constant R is;V=IR, so it is a direct linear relation.
4. A
This is another direct linear relation as P=IV.
5. D
The relation between P, R, and V is P=, so P is inversely proportional to R.
6.B
The relation between P,I, and R is , so P is directly proportional to the square of I.

Please note that y:x relations are always straight lines while  relations are parabolic lines.

Hope this helps!
5 0
3 years ago
A car with a speed of 50ms is stopped when its brakes are pressed. The displacement passed before stopping is 150 m. How much de
monitta
I dont think it can be solved as time is not mentioned
8 0
3 years ago
In the javelin throw at a track-and-field event, the javelin is launched at a speed of 29 m/s at an angle of 36???? above the ho
netineya [11]

Answer:

t = 0.96 s  is the time it takes for the angle to reduce

Explanation:

In the launch of projectiles, the velocity is broken down into its x and y components, the velocity in the x-axis is constant, as there is no acceleration, instead the velocity in the axis and is reduced by the effect of the acceleration of gravity.

We can find Vox for the initial conditions

  Voy  = Vo sin θ

  Voy = 29 sin 36

  VoY = 17 m/s

  Vox = Vo cos θ

  Vox = 29 cos 36

  Vox= 23.5 m/s

  Vx = Vox  

The velocity on the x axis is constant

By trigonometry, we find the firing angle

 

  tan θ = Voy/ Vx

  Vy = Vx tan θ

  Vy = 23.5 tan 18

  Vy = 7.64 m/s

Now that we have the vertical speed we can find the time

   Vy = I'm going - g t

   t = (Vy -Voy) / g

   t = (17 - 7.64) /9.8

   t = 0.96 s

Be the time it takes for the angle to reduce

6 0
3 years ago
Which of the following is an example of a primary source?
astra-53 [7]

Answer:

scientific journal

in my guess

6 0
3 years ago
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