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Blababa [14]
3 years ago
5

Identify each statement as an example of melting or sublimation,

Physics
1 answer:
xeze [42]3 years ago
5 0

1st is sublimation

2and is melting

3red is melting

4th is sublimation

sublimation is just "skipping" the liquid phase / state

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a ball is thrown down from a building with an initial of 10 m/s and hits the ground with a velocity of 51 m/s how tall is the bu
olga55 [171]

Answer:

41

Explanation:

you subtract the initial velocity which is 10m/s from the final velocity which is 51m/s

5 0
3 years ago
How was Edwin Hubble able to use his discovery of Cepheids in Andromeda to prove that the "spiral nebulae" were actually galaxie
Ad libitum [116K]

Answer:  The correct answer is :  From the period-luminosity relation for Cepheids, he was able to determine the distance to Andromeda and show that it was far outside the Milky Way Galaxy.

Explanation:  Hubble's law says that the recession velocity of a galaxy is directly proportional to its distance from us. Hubble measured the distance to the Andromeda galaxy by applying the period-luminosity relationship to Cepheid.

7 0
4 years ago
A sample of nitrogen gas has a volume of 5.0 ml at a pressure of 1.50 atm. what is the pressure exerted by the gas if the volume
olchik [2.2K]

A sample of nitrogen gas has a volume of 5.0 ml at a pressure of 1.50 atm. what is the pressure exerted by the gas if the volume increases to 30.0 ml, at constant temperature is 0.25atm.

On constant temperature, the pressure and volume relation become constant before and after the change in quantitities have occurred.

According to Boyle's Law,

P₁V₁ = P₂V₂

where, P₁ is pressure exerted by the gas initially

V₁ is the volume of gas initially

P₂ is pressure exerted by the gas finally

V₂ is the volume of gas finally

Given,

P₁ = 1.5 atm

V₁ = 5 ml

V₂ = 30 ml

P₂ =?

On substituting the given values in the above equation:

P₁V₁ = P₂V₂

1.5 atm × 5 ml = P₂ × 30 ml

P₂ = 0.25 atm

Hence, pressure exerted by the gas is 0.25atm.

Learn more about Boyle's Law here, brainly.com/question/1437490

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8 0
2 years ago
10. What is the a) Period and b) frequency of a mass spring system using a 12 kg mass and a spring with a k value of 2200N/m?
harkovskaia [24]

Answer:

Part a)

Time period of spring block system is

T = 0.464 s

Part b)

Frequency of spring block system is

f = 2.15 Hz

Explanation:

As we know that the time period of spring mass system is given as

T = 2\pi\sqrt{\frac{M}{k}}

now we have

M = 12 kg

k = 2200 N/m

now we have

T = 2\pi\sqrt{\frac{12}{2200}}

T = 0.464 s

Part b)

As we know that time period of spring block system is inversely dependent on the frequency

so we have

f = \frac{1}{T}

f = \frac{1}{0.464}

f = 2.15 Hz

3 0
3 years ago
Eroded heavy minerals settle from moving water what forms from this
vladimir1956 [14]
Rocks- Mountains.....
6 0
4 years ago
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