There are fiber optic telephone cables connecting North America and Europe, lying on the bottom of the Atlantic ocean. The wire
1 answer:
Answer:
The time taken is
Explanation:
From the question we are told that
The length of the wire is
The refractive index is
The velocity of the signal is mathematically represented as
Where c is the speed of light with value
substituting values
The time taken is mathematically evaluated as
substituting values
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This problem uses the relationships among current I, current density J, and drift speed vd. We are given the total of electrons that pass through the wire in t = 3s and the area A, so we use the following equation to to find vd, from J and the known electron density n, so:
<span>The current I is any motion of charge from one region to another, so this is given by:
</span>
The magnitude of the current density is:
Being:
<span>
Finally, for the drift velocity magnitude vd, we find:
</span>
Notice: The current I is very high for this wire. The given values of the variables are a little bit odd
<span>The current I is any motion of charge from one region to another, so this is given by:
</span>
The magnitude of the current density is:
Being:
<span>
Finally, for the drift velocity magnitude vd, we find:
</span>
Notice: The current I is very high for this wire. The given values of the variables are a little bit odd
Explanation:
According to the law of conservation of energy,
......... (1)
As we know that, P.E = mgh
and, K.E =
Therefore, putting these values of P.E and K.E into equation (1) as follows.
Now, initial case is that its starts with 50.3 m/s at bottom.
P.E = m and PE = 0
And, as it reaches the height h,
P.E = mgh
So, K.E will be m
Hence, speed = 6 m/s