<span>ABCD is an isosceles trapezoid with legs AB and CD
∴ AB = CD
</span>
<span>AB = 6y +5
</span>
<span>CD= 2y +1
∴ 6y + 5 = 2y + 1
6y - 2y = 5 - 1
4y = 4
∴ y = 4/4 = 1
</span>
Answer:
Cubic trinomial
Step-by-step explanation:
The degree of a term is the sum of the exponents of its variables
- Quadratic: a polynomial of degree two
- Cubic: a polynomial of degree three
Therefore, -5x³ - 4x + 1 is a cubic (since the sum of the exponents is 3)
- monomial: a polynomial with exactly one term
- binomial: a polynomial with exactly two terms
- trinomial: a polynomial with exactly three terms
Therefore, -5x³ - 4x + 1 is a trinomial (as it has exactly 3 terms)
Answer:
⇒ 40 cm
Step-by-step explanation:
Given:
Height of cubes used by Nelson = 8 cm
Height of cubes used by Andrews = 10 cm
Solution:
Nelson made a stack of cubes where the height of the cubes is 8 cm, so the multiplication of the cube height is.
⇒ ![8, 16, 24, 32, 40, 48, 56....](https://tex.z-dn.net/?f=8%2C%2016%2C%2024%2C%2032%2C%2040%2C%2048%2C%2056....)
Similarly Andrew also made a stack of cubes where the height of the cubes is 10 cm, so the multiplication of the cube height is.
⇒ ![10, 20, 30, 40, 50, 60.....](https://tex.z-dn.net/?f=10%2C%2020%2C%2030%2C%2040%2C%2050%2C%2060.....)
We can see the shortest same height of the both stack is 40 cm.
Therefore, 40 cm is the shortest possible stake height for both.
Answer:
The age of Mr. Collins is 30 years and
The model which represent the problem is, The age of Mr. Collins is 3 × 10
Step-by-step explanation:
Given as :
The age of Adam = 10 years
The age of Mr. Collins = x years
The age of Mr. Collins = 3 times the age of Adam
Or, x = 3 × The age of Adam
Or, x = 3 × 10
∴ x = 30
So, The age of Mr. Collins = x years = 30 years
The model which represent the problem is, The age of Mr. Collins = 3 × 10
Hence The age of Mr. Collins is 30 years and
The model which represent the problem is, The age of Mr. Collins = 3 × 10
Answer
Answer:
see below
Step-by-step explanation:
There are two points where y = -3
at x = -2 and x = 1
when x = 0 f(0) = 1