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3 years ago

SECTION B

Mathematics

1 answer:

yarga [219]3 years ago

3 0

9514 1404 393

Answer:

180 km

Step-by-step explanation:

The Nissan had traveled (120 km/h)(1/3 h) = 40 km when it had the puncture. It started from that location when the puncture was repaired at t = (1/3+1/2) = 5/6, where t is in hours. Then the two vehicles met (again) when ...

Matatu distance = Nissan distance

90t = 40+120(t -5/6)

0 = 40 +30t -100 . . . . . . subtract 90t, eliminate parentheses

60 = 30t . . . . . . . . . . . add 60

2 = t . . . . . . . . . . . . . 2 hours after leaving, the cars meet again

That distance from town A is ...

y = 90t = 90(2) = 180 . . . . km

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a. 0.0001

b. 0.6561

c. 0.3439

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Step-by-step explanation:

a. # We are given that the probability that a person in the United States has Type B+ blood = 0.10. Also we are told that four unrelated people in the United States are selected at random.

#We have to find here the probability that all four have type B+ blood.

Since the events are independent, we have :

Probability that all four have B+ blood = 0.10 x 0.10x 0.10x0.10

= 0.0001

Therefore, the probability that all four have type B+ blood is 0.0001

b. We have to find the probability that none have B+ blood. Using the complementary law of probability we have:

Probability that blood type is not B+ = 1 - 0.10= 0.90

Therefore, the probability that none have B+ blood

= 0.90 x 0.90 x 0.90x0.90=0.6561

Therefore, the probability that none have B+ blood is 0.6561

c. We have to find the probability that at least one of the four have B+ blood.

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Therefore,the probability that at least one of the four has type B+ blood is 0.3439

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