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svp [43]
3 years ago
6

(c^3b^1a^4)^4 + 3a^16b^4c^12

Mathematics
1 answer:
azamat3 years ago
5 0

Answer: 4a16b4c12

Step-by-step explanation:

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Let a and b be non-zero integers
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The correct answer is d

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6 0
4 years ago
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A gift box’s rectangular base has a perimeter of 92 centimeters. The length of the base is one more than twice the base’s width.
kozerog [31]
Assume that the length of the rectangle is "l" and that the width is "w".

We are given that: 
(1) The length is one more than twice the base. This means that:
l = 2w + 1 .......> equation I
(2) The perimeter is 92 cm. This means that:
92 = 2(l+w) ...........> equation II

Substitute with equation I in equation II to get the width as follows:
92 = 2(l+w)
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Substitute with w in equation I to get the length as follows:
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l = 30 + 1 = 31

Based on the above calculations:
length of base = 31 cm
width of base = 15 cm
3 0
3 years ago
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