(3y^7)^3 3^3*y^(7*3)
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9y^9 9*y^9
(3y^7)^3 3^3*y^(7*3) 27*y^21 (mult. together the exponents 3 and 7)
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9y^9 9*y^9 9*y^9
That 27/9 reduces to 3. y^(21) / y^9 reduces to y^12.
Thus, we obtain 3*y^12 (answer)
Please do the next one, asking questions if need be, and showing your work.
Answer:

Step-by-step explanation:
Notice that angles <1 and <3 are opposed by the vertex, which makes them of equal measure, therefore, <1 = 47 degrees.
Notice as well that angles <1 and <2 combine into a straight line, therefore, they are supplementary angles whose addition gives 180 degrees then we can find the value of angle <2 via:

And finally, angle <4 is opposite through the vertex to angle <2, and therefore they must have the same measure. So, <4 = 133 degrees.
IT is A 44 degrees i hope this helps
The cross section is a rectangle, which is a type of square.
Answer: ?
Step-by-step explanation: