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2 years ago

Our school planned to plant 150 seedlings in a tree planting activity. However,

Mathematics

1 answer:

Nadya [2.5K]2 years ago

8 0

Answer:

90 seedlings

Step-by-step explanation:

Total seedlings to plant = 150

Percentage of seedlings planted = 60%

How many seedlings did we plant during that day?

Number of seedlings planted for that day = 60% of 150

= 0.6 × 150

= 90 seedlings

Number of seedlings planted for that day = 90 seedlings

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The product of x and 2 is less than or equal to 4

MissTica

2x≤4

I'm not sure how else to help you in this situation, without you providing me with more information. If you want the solution for x, you would just divide both sides by the coefficient of the variable, or 2, resulting in the inequality:

x ≤ 2

Hope this helps! Comment if you need to add info or have any more questions about this problem.

5 0

3 years ago

A city has a populations of 38,802,500 people. estimate the population ot hte nearest ten million

Zolol [24]

Answer:

39,000,000

Roundend to the nearest 1,000,000 or

the Millions Place.

38,802,500.0000000

Roundend to the nearest 0.0000001 or

the Ten Millionths Place.

8 0

3 years ago

Find the scale factor of the smaller figure to the larger figure

guapka [62]

Answer:

#9: 1.2

#10: 1.25

Step-by-step explanation:

To find the scale factor of the smaller figure to the larger figure, we're going to be dividing the measurements of corresponding edges.

$\frac{larger figure}{smaller figure}$

If you wanted to find the scale factor of the larger figure to the smaller figure, you'd do: $\frac{smaller figure}{larger figure}$

Question #9:

Left edges: $\frac{larger figure}{smaller figure}$ ⇒ $\frac{24}{20}$ = 1.2

Bottom edges: $\frac{larger figure}{smaller figure}$ ⇒ $\frac{30}{25}$ = 1.2

(You should get the same number as long as the figures are similar.)

Question #10:

Bottom edges: $\frac{larger figure}{smaller figure}$ ⇒ $\frac{30}{24}$ = 1.25

(There are no corresponding edges with measurements that we can compare.)

~Hope this helps!~

4 0

3 years ago

A ½in diameter rod of 5in length is being considered as part of a mechanical linkagein which it can experience a tensile loading

Evgesh-ka [11]

Answer:

a. Maximum Load = Force = 27085.09 N

b. Maximum Energy = 3.440 Joules

Step-by-step explanation:

Given

Rod diameter = ½in = 0.5in

Length = 5in

Young's modulus = 15.5Msi

By applying the 0.2% offset rule,

The maximum load the rod can hold before it gets to breaking point is given as follows by taking the strain as 0.2%

Young Modulus = Stress/Strain ------- Make Stress the Subject of Formula

Stress = Strain * Young Modulus

Stress = 0.2% * 15.5

Stress = 0.002 * 15.5

Stress = 0.031Msi

Calculating the area of the rod

Area = πr² or πd²/4

Area, A = 22/7 * 0.5^4 / 4

A = 22/7 * 0.25 / 4

A = 5.5/28

A = 0.1964in²

The maximum load that the rod would take before it starts to permanently elongate is given by

Force = Stress * Atea

Force = 0.031Msi * 0.1964in²

Force = 31Ksi * 0.1964in²

Force = 6.089Ksi in²

Force = 6.089 * 1000lbf

Force = 6089 lbf

1 lbf = 4.4482N

So, Force = 6089 * 4.4482N

Force = 27085.09 N

Using Strain to Energy Formula

U = V×σ²/2·E

Where V = Volume

V = Length * Area

V = 5 in * 0.1964in²

V = 0.982in³

σ = Stress = 0.031Msi

= 0.031 * 1000Ksi

= 31Ksi

= 31 * 1000psi

= 31000psi

E = Young Modulus = 15.5Msi

= 15.5 * 1000Ksi

= 15.5 * 1000 * 1000psi

= 15500000psi

So,

Energy = 0.982 * 31000²/ ( 2 * 15500000)

Energy = 943,702,000/31000000

Energy = 30.442in³psi

------- Converted to ftlbf

Energy = 2.537 ftlbf

-------- Converted to Joules

Energy = 3.440 Joules

7 0

3 years ago

Which is the slope of the line that passes through the points (3,17) and (7,25)? a slope = 1/2 b slope = 2 c slope = −2 d slope

Ierofanga [76]

Slope is y2-y1/x2-x1
so, 25-17/7-3
8/4=2
The answer should be b

5 0

3 years ago