How to graph absolute value functions?

An aircraft has a total time in service of 468 hours. The Airworthiness Directive given was initially complied with at 454 hours

Georgia [21]

Answer:

440 hours

Step-by-step explanation:

In this case the aircraft has completed one cycle of service in the first 454 hours of service. Then making the difference between the hours of service and the hours of the first cycle we have:

Hours of the second cycle= Total time in service- time Airworthiness Directive

=468-454=14

Then we have 14 hours of service and need to accumulate the rest to complete 454. It is

454-14=440

Then we need to accumulate 440 hours additional to complete the Airworthiness Directive .

6 0

2 years ago

What is 30 less than 4 times a number is equal to 14

Genrish500 [490]

The answer is x=11
4x-30=14
You add 30 to each side=4x=44
Then you divide 44 by 4 which=11

4 0

2 years ago

Help with this problem^

Fittoniya [83]

This formula is the exposition of 8 and equals to 6 how u ask ? well if u 8 minus 2 u get 6 than add 6

6 0

3 years ago

HELP PLEASE A. 51.4 B. 50.0 C. 31.0 D. 39.5 E. None

Liono4ka [1.6K]

First, in order to find the length of side w, you must first find the angle W.
A triangle must be 180 degrees in total. 93 + 37 makes the triangle only have 130 at the moment.
180 - 130 = 50
So angle W is 50 degrees
Now using this, we can use law of sines.
$\frac{w}{sin50} = \frac{31}{sin37}$
Now multiply sin 50 on both sides. It can be written like so:
$\frac{31sin50}{sin37}$
Now plug this in a calculator.
Answer is 39.5

8 0

3 years ago

A consumer products company is formulating a new shampoo and is interested in foam height (in mm). Foam height is approximately

Genrish500 [490]

Answer:

a) 0.057

b) 0.5234

c) 0.4766

Step-by-step explanation:

a)

To find the p-value if the sample average is 185, we first compute the z-score associated to this value, we use the formula

$z=\frac{\bar x-\mu}{\sigma/\sqrt N}$

where

$\bar x=mean\; of\;the \;sample$

$\mu=mean\; established\; in\; H_0$

$\sigma=standard \; deviation$

N = size of the sample.

So,

$z=\frac{185-175}{20/\sqrt {10}}=1.5811$

$\boxed {z=1.5811}$

As the sample suggests that the real mean could be greater than the established in the null hypothesis, then we are interested in the area under the normal curve to the right of 1.5811 and this would be your p-value.

We compute the area of the normal curve for values to the right of 1.5811 either with a table or with a computer and find that this area is equal to 0.0569 = 0.057 rounded to 3 decimals.

So the p-value is

$\boxed {p=0.057}$

b)

Since the z-score associated to an α value of 0.05 is 1.64 and the z-score of the alternative hypothesis is 1.5811 which is less than 1.64 (z critical), we cannot reject the null, so we are making a Type II error since 175 is not the true mean.

We can compute the probability of such an error following the next steps:

Step 1

Compute $\bar x_{critical}$